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6 The graph shows information about the average monthly temperature, in °C, in Amman.
| Answer | Mark | Mark scheme |
|---|---|---|
| 6 | B1 | cao |
| Answer | Mark | Mark scheme |
|---|---|---|
| May, October | B1 | cao |
9 The graph shows information about the number of houses sold by an estate agent in each of six months last year.
| Answer | Mark | Mark scheme |
|---|---|---|
| 23 | B1 | cao |
| Answer | Mark | Mark scheme |
|---|---|---|
| 10 : 56 | M1 | for 10 or 56 identified |
| A1 | for 10 : 56 or any other equivalent ratio |
56 : 10 implies this mark only
Accept 1 : 5.6
27 Sean has drawn a time series graph to show the numbers, in thousands, of visitors to a fun park.
Write down two things that are wrong or could be misleading with this graph. (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| statement | B2 | Two different statements Acceptable eg should be joined with straight lines (not curve)/should use a ruler 1st (quarter) not shown/plotted/labelled/not all quarters labelled does not show all 4 seasons 9.5 missing from vertical axes/not linear vertical (number) axis does not start at 0/the \(y\) axis starts at 6 the graph does not begin at 0, it starts at 6 it is not clear what 2, 3, 4 on the \(x\)-axis mean the scale of years doesn’t make sense there is lack of clarity about what the numbers on the \(x\) axis represent graph is curved line Not acceptable eg no value plotted for 2 in 2016 it does not start at 0 (no reference to vertical axis)/missing 0 they should not have connected the dots like that the numbers on the \(x\) axis are repeated the numbers along the \(x\) axis 2, 3, 4 the years on the \(x\) axis have not been written properly does not follow a sequence it needs a discontinuity wiggle on the axis no title |
| (B1 | One statement eg from those above.) |
Ignore additional statements provided no contradiction
8 Chrissy drew this graph to show the percentage of buses that got to a bus stop on time for six months.
| Answer | Mark | Notes |
|---|---|---|
| Statement | C1 | States one thing wrong eg vertical scale is not linear oe |
| Answer | Mark | Notes |
|---|---|---|
| Trend described | C1 | eg the trend is upwards, positive (trend) oe |
20 Youssuf posted an advert on his social media channel.
The table shows the number of views of the advert during its first 6 days.
| Day | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| Number of views | 49 000 | 95 000 | 87 000 | 77 000 | 64 000 | 48 000 |
Estimate how much he receives from views of the advert on day 7 [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| All six given points plotted correctly and joined with straight lines | B2 | \(\pm\) half square B1 at least four of the given points plotted correctly |
Mark intention for straight lines
Lines can be dashed (do not regard as short lines if intention clear) or continuous
Ignore lines drawn to the left of day 1 and to the right of day 6
The top of the lines in a vertical line graph can imply points plotted correctly (other vertical lines can be ignored)
Ignore horizontal lines
Ignore extra points
Ignore a line of best fit and/or a histogram and/or a bar chart
| Answer | Mark | Comments |
|---|---|---|
| [20 000, 40 000] | B1 | may be implied |
| their [20 000, 40 000] \(\times\) 0.018 (\(\div\) 100) or [360, 720] (\(\div\) 100) | M1 | oe eg their [20 000, 40 000] \(\times\) 0.000 18 1000 \(\lt\) their [20 000, 40 000] \(\lt\) 48 000 condone 0.02 for 0.018 |
| [3.60, 7.20] | A1ft | ft B0M1 answer must be an amount of money |
| Accept an answer in pence only if £ has been crossed out and p(ence) is given | |
| For A1 or A1ft accept answers rounded or truncated to the nearest penny eg \(28\,700 \times 0.018 \div 100\) Answer 5.17 (or 5.16) | B1M1A1 |
| Using 0.02 can score a maximum of B1M1A0 eg1 \(30\,000 \times 0.02 = 600\) Answer 6 eg2 \(46\,000 \times 0.02 = 920\) Answer 9.20 | B1M1A0 B0M1A0 |
| Estimating their final answer can score a maximum of B1M1A0 unless correct answer also seen eg1 \(32\,000 \times 0.018 \div 100\) Answer 5.80 eg2 \(32\,000 \times 0.018 \div 100 = 5.76\) Answer 5.80 | B1M1A0 B1M1A1 |
| \(30\,000 \times 0.018\) Answer 5.4 | B1M1A0 |
| If part (b) is blank, B1 may be awarded for [20 000, 40 000] unambiguously stated for day 7 in part (a) |
3 Youssuf posted an advert on his social media channel.
The table shows the number of views of the advert during its first 6 days.
| Day | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| Number of views | 49 000 | 95 000 | 87 000 | 77 000 | 64 000 | 48 000 |
Estimate how much he receives from views of the advert on day 7 [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| All six given points plotted correctly and joined with straight lines | B2 | \(\pm\) half square B1 at least four of the given points plotted correctly |
Mark intention for straight lines
Lines can be dashed (do not regard as short lines if intention clear) or continuous
Ignore lines drawn to the left of day 1 and to the right of day 6
The top of the lines in a vertical line graph can imply points plotted correctly (other vertical lines can be ignored)
Ignore horizontal lines
Ignore extra points
Ignore a line of best fit and/or a histogram and/or a bar chart
| Answer | Mark | Comments |
|---|---|---|
| [20 000, 40 000] | B1 | may be implied |
| their [20 000, 40 000] \(\times\) 0.018 (\(\div\) 100) or [360, 720] (\(\div\) 100) | M1 | oe eg their [20 000, 40 000] \(\times\) 0.000 18 1000 \(\lt\) their [20 000, 40 000] \(\lt\) 48 000 condone 0.02 for 0.018 |
| [3.60, 7.20] | A1ft | ft B0M1 answer must be an amount of money |
| Accept an answer in pence only if £ has been crossed out and p(ence) is given | |
| For A1 or A1ft accept answers rounded or truncated to the nearest penny eg \(28\,700 \times 0.018 \div 100\) Answer 5.17 (or 5.16) | B1M1A1 |
| Using 0.02 can score a maximum of B1M1A0 eg1 \(30\,000 \times 0.02 = 600\) Answer 6 eg2 \(46\,000 \times 0.02 = 920\) Answer 9.20 | B1M1A0 B0M1A0 |
| Estimating their final answer can score a maximum of B1M1A0 unless correct answer also seen eg1 \(32\,000 \times 0.018 \div 100\) Answer 5.80 eg2 \(32\,000 \times 0.018 \div 100 = 5.76\) Answer 5.80 | B1M1A0 B1M1A1 |
| \(30\,000 \times 0.018\) Answer 5.4 | B1M1A0 |
| If part (b) is blank, B1 may be awarded for [20 000, 40 000] unambiguously stated for day 7 in part (a) |
19 The table shows information about the number of houses with solar panels in a town.
| Year | 2017 | 2018 | 2019 | 2020 | 2021 | 2022 |
|---|---|---|---|---|---|---|
| Number of houses | 50 | 65 | 115 | 210 | 275 | 350 |
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 2 points correctly | M1 | \(\pm\dfrac{1}{2}\) square |
| Fully correct with all points joined by single straight lines | A1 | \(\pm\dfrac{1}{2}\) square |
| Mark intention | |
| Ignore other points plotted and any lines of best fit | |
| Points may be implied by the position of the line | |
 | M1A1 |
| Answer | Mark | Comments |
|---|---|---|
| [360, 500] | B1 |
| An interval given entirely in range eg 425 – 440 | B1 |
| An interval given not entirely in range eg 340 – 430 | B0 |
2 The table shows information about the number of houses with solar panels in a town.
| Year | 2017 | 2018 | 2019 | 2020 | 2021 | 2022 |
|---|---|---|---|---|---|---|
| Number of houses | 50 | 65 | 115 | 210 | 275 | 350 |
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 2 points correctly | M1 | \(\pm\dfrac{1}{2}\) square |
| Fully correct with all points joined by single straight lines | A1 | \(\pm\dfrac{1}{2}\) square |
| Mark intention | |
| Ignore other points plotted and any lines of best fit | |
| Points may be implied by the position of the line | |
 | M1A1 |
| Answer | Mark | Comments |
|---|---|---|
| [360, 500] | B1 |
| An interval given entirely in range eg 425 – 440 | B1 |
| An interval given not entirely in range eg 340 – 430 | B0 |
21 The table shows the number of workers at a company in different years.
| Year | 2015 | 2016 | 2017 | 2018 | 2019 | 2020 | 2021 | 2022 |
|---|---|---|---|---|---|---|---|---|
| Number of workers | 29 | 34 | 42 | 52 | 62 | 70 | 76 | 80 |
A time-series graph is drawn to represent the data.
The first four points have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| At least 3 points correctly plotted | M1 | \(\pm \dfrac{1}{2}\) square |
| All 4 points correctly plotted and joined with straight lines | A1 | \(\pm \dfrac{1}{2}\) square lines may be dashed |
Mark intention for straight lines
Condone one continuous, smooth curve
Ignore the graph before 2015 and after 2022
Ignore a line of best fit
| Answer | Mark | Comments |
|---|---|---|
| [82, 90] | B1 |
| Answer in range with or without working, with no graph or incorrect graph | B1 |
6 The table shows the number of workers at a company in different years.
| Year | 2015 | 2016 | 2017 | 2018 | 2019 | 2020 | 2021 | 2022 |
|---|---|---|---|---|---|---|---|---|
| Number of workers | 29 | 34 | 42 | 52 | 62 | 70 | 76 | 80 |
A time-series graph is drawn to represent the data.
The first four points have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| At least 3 points correctly plotted | M1 | \(\pm\dfrac{1}{2}\) square |
| All 4 points correctly plotted and joined with straight lines | A1 | \(\pm\dfrac{1}{2}\) square lines may be dashed |
Mark intention for straight lines
Condone one continuous, smooth curve
Ignore the graph before 2015 and after 2022
Ignore a line of best fit
| Answer | Mark | Comments |
|---|---|---|
| [82, 90] | B1 |
| Answer in range with or without working, with no graph or incorrect graph | B1 |
23 The time students spent watching TV was recorded.
The table shows the average daily time per student each year from 2012 to 2019
| Year | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 | 2018 | 2019 |
|---|---|---|---|---|---|---|---|---|
| Time (minutes) | 157 | 148 | 138 | 124 | 113 | 100 | 90 | 82 |
A time series graph is drawn to represent the data.
The first four points have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 3 points correctly | M1 | \(\pm\dfrac{1}{2}\) square |
| All four points correctly plotted and joined | A1 | \(\pm\dfrac{1}{2}\) square ignore working for part (b) |
\(\pm\dfrac{1}{2}\) square means half a small square horizontally and vertically
If a point is within tolerance the line must be within \(\pm\dfrac{1}{2}\) square of their point
Mark intention for joining point to point
| Answer | Mark | Comments |
|---|---|---|
| [70, 78] | B1 |
| Answer in range with or without working, with no graph or incorrect graph | B1 |
| 70.5 – 75 on answer line (both values in range) | B1 |
5 The time students spent watching TV was recorded.
The table shows the average daily time per student each year from 2012 to 2019
| Year | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 | 2018 | 2019 |
|---|---|---|---|---|---|---|---|---|
| Time (minutes) | 157 | 148 | 138 | 124 | 113 | 100 | 90 | 82 |
A time series graph is drawn to represent the data.
The first four points have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 3 points correctly | M1 | \(\pm\dfrac{1}{2}\) square |
| All four points correctly plotted and joined | A1 | \(\pm\dfrac{1}{2}\) square ignore working for part (b) |
\(\pm\dfrac{1}{2}\) square means half a small square horizontally and vertically
If a point is within tolerance the line must be within \(\pm\dfrac{1}{2}\) square of their point
Mark intention for joining point to point
| Answer | Mark | Comments |
|---|---|---|
| [70, 78] | B1 |
| Answer in range with or without working, with no graph or incorrect graph | B1 |
| 70.5 – 75 on answer line (both values in range) | B1 |
24 A music festival has taken place each year from 2011
The table shows the number of people who attended each year.
| Year | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 | 2018 |
|---|---|---|---|---|---|---|---|---|
| Number of people | 350 | 583 | 906 | 1471 | 2023 | 2612 | 3251 | 3780 |
The festival organisers draw a time series graph to represent the data.
The first four years have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 3 points correctly | M1 | Plots within the correct 2 mm vertical square |
| Fully correct with all points joined | A1 |
| Answer | Mark | Comments |
|---|---|---|
| [4200, 4500] | B2 | B1 Any indication the 2018 figure is being increased for 2019 eg a point plotted for 2019 that is greater than 3780 |
| Answer in range with or without working | B2 |
| 4300 – 4350 on answer line (both values in range) | B2 |
| 4400 – 4600 on answer line (one value in range) | B1 |
| Answer outside of range but between 3780 and 4200 | B1 |
| Answer outside of range but greater than 4500 | B1 |
6 A music festival has taken place each year from 2011
The table shows the number of people who attended each year.
| Year | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 | 2018 |
|---|---|---|---|---|---|---|---|---|
| Number of people | 350 | 583 | 906 | 1471 | 2023 | 2612 | 3251 | 3780 |
The festival organisers draw a time series graph to represent the data.
The first four years have been plotted.
| Answer | Mark | Comments |
|---|---|---|
| Plots at least 3 points correctly | M1 | Plots within the correct 2 mm vertical square |
| Fully correct with all points joined | A1 |
| Answer | Mark | Comments |
|---|---|---|
| [4200, 4500] | B2 | B1 Any indication the 2018 figure is being increased for 2019 eg a point plotted for 2019 that is greater than 3780 |
| Answer in range with or without working | B2 |
| 4300 – 4350 on answer line (both values in range) | B2 |
| 4400 – 4600 on answer line (one value in range) | B1 |
| Answer outside of range but between 3780 and 4200 | B1 |
| Answer outside of range but greater than 4500 | B1 |
14 Chris sells lawnmowers.
The table shows the number he sold each quarter for three years.
| Quarter 1 | Quarter 2 | Quarter 3 | Quarter 4 | |
|---|---|---|---|---|
| 2016 | 17 | 64 | 50 | 5 |
| 2015 | 9 | 72 | 61 | 1 |
| 2014 | 19 | 58 | 53 | 2 |
You must show your working. [2 marks]
At the start of which quarter should Chris stock the most lawnmowers?
Circle your answer. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| Two of the three totals correct (2016 =) 136 (2015 =) 143 (2014 =) 132 or 17 + 64 + 50 + 5 and 9 + 72 + 61 + 1 and 19 + 58 + 53 + 2 | M1 | Totals may be seen by table Correct totals may be implied by means (2016 \(\rightarrow\) 34, 2015 \(\rightarrow\) 35.75, 2014 \(\rightarrow\) 33) Addition signs must be shown for horizontal addition but may be implied by a column of numbers in their working |
| 136 and 143 and 132 and 2015 or 34 and 35.75 and 33 and 2015 | A1 | Totals may be seen by table |
| Alternative method 2 | ||
| 8 and –8 and –11 and 4 or –7 and –10 and 14 and 8 and –1 or 11 | M1 | Difference between 2016 and 2015 Difference between 2015 and 2014 Differences may be seen in table |
| –7 and 11 and 2015 | A1 | Differences may be seen in table |
| Differences may have consistently opposite signs for either comparison | |
| Ignore totals for quarters shown | |
| Allow Year 2 for 2015 | |
| 136 and 143 and 132, answer 143 | M1A0 |
| 136 and 143 and 132, answer 143 in 2015 | M1A1 |
| Answer | Mark | Comments |
|---|---|---|
| Quarter 2 | B1 |
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