3 Youssuf posted an advert on his social media channel.
The table shows the number of views of the advert during its first 6 days.
Day
1
2
3
4
5
6
Number of views
49 000
95 000
87 000
77 000
64 000
48 000
(a) On the grid, draw a time series graph to represent the data. [2 marks]
(b) Youssuf receives 0.018p for each view of the advert.
Estimate how much he receives from views of the advert on day 7[3 marks]
Mark scheme (a)
Answer
Mark
Comments
All six given points plotted correctly and joined with straight lines
B2
\(\pm\) half square B1 at least four of the given points plotted correctly
Additional guidance
Mark intention for straight lines
Lines can be dashed (do not regard as short lines if intention clear) or continuous
Ignore lines drawn to the left of day 1 and to the right of day 6
The top of the lines in a vertical line graph can imply points plotted correctly (other vertical lines can be ignored)
Ignore horizontal lines
Ignore extra points
Ignore a line of best fit and/or a histogram and/or a bar chart
Mark scheme (b)
Answer
Mark
Comments
[20 000, 40 000]
B1
may be implied
their [20 000, 40 000] \(\times\) 0.018 (\(\div\) 100) or [360, 720] (\(\div\) 100)
M1
oe eg their [20 000, 40 000] \(\times\) 0.000 18 1000 \(\lt\) their [20 000, 40 000] \(\lt\) 48 000 condone 0.02 for 0.018
[3.60, 7.20]
A1ft
ft B0M1 answer must be an amount of money
Additional guidance
Accept an answer in pence only if £ has been crossed out and p(ence) is given
For A1 or A1ft accept answers rounded or truncated to the nearest penny eg \(28\,700 \times 0.018 \div 100\) Answer 5.17 (or 5.16)
B1M1A1
Using 0.02 can score a maximum of B1M1A0 eg1 \(30\,000 \times 0.02 = 600\) Answer 6 eg2 \(46\,000 \times 0.02 = 920\) Answer 9.20
B1M1A0 B0M1A0
Estimating their final answer can score a maximum of B1M1A0 unless correct answer also seen eg1 \(32\,000 \times 0.018 \div 100\) Answer 5.80 eg2 \(32\,000 \times 0.018 \div 100 = 5.76\) Answer 5.80
B1M1A0 B1M1A1
\(30\,000 \times 0.018\) Answer 5.4
B1M1A0
If part (b) is blank, B1 may be awarded for [20 000, 40 000] unambiguously stated for day 7 in part (a)