Numeracy Intermediate June 2019 Unit 1 Q3
3. Aled and Gareth went on holiday to France.
- Aled’s mother paid \(\dfrac{1}{3}\) of the total cost.
- Aled and Gareth shared the remaining cost in the ratio 1 : 9.
Aled’s mother paid £ ……………
Aled paid £ ……………
Gareth paid £ ……………
This was over the maximum of 20 kg allowed.
Gareth removed items from his luggage so that its mass was:
- as close to 20 kg as possible,
- not greater than 20 kg.
From the following list of items, which two items did Gareth remove?
You must show all your working. [3]
| Coat | Headphones | Jumper | Book | Hat |
| 820 g | 300 g | 320 g | 340 g | 200 g |

Use Aled’s conversion graph to answer the following questions.
How much is this in euros? [2]
Camera costs …………… euros
How much is this in euros? [2]
Meal costs …………… euros
He recorded the exchange rates for the previous 60 days, as shown below.
| £1 = \(b\) euros | Frequency |
|---|---|
| \(1.00 \leqslant b \lt 1.04\) | 2 |
| \(1.04 \leqslant b \lt 1.08\) | 8 |
| \(1.08 \leqslant b \lt 1.12\) | 16 |
| \(1.12 \leqslant b \lt 1.16\) | 33 |
| \(1.16 \leqslant b \lt 1.20\) | 1 |
Gareth started to draw a frequency diagram to show this information.

Circle your answer. [1]
60 \(1.08 \leqslant b \lt 1.12\) 33 \(1.12 \leqslant b \lt 1.16\) 16
| Scheme | Marks | Comments |
|---|---|---|
| (i) (Aled’s mum paid) (£) 220 OR (Aled and Gareth pay a total of 660 – 220) (£)440 | B1 | |
| (660 – 220) ÷ (1 + 9) or 9 × (660 – 220) ÷ (1 + 9) or 44 or 9 × 44 | M1 | FT 660 – ‘their derived 220’ |
| (Aled paid) (£) 44 | A1 | |
| (Gareth paid) (£) 396 | A1 | FT 9 × 'their 44' FT 440 – 'their 44' provided M1 awarded (this allows If answers 44 and 396 are reversed, M1, A0, A1 to be awarded) If M0, A0, A0 award SC1 for any of the following
|
| (ii) Explanation, e.g. 220 + 44 + 396 (= 660), 'add them all up', 'check to see if the total is (£)660', 'divide Gareth's amount by 9' | E1 | Depends on at least 1 mark awarded in 3(a)(i) Mark as appropriate to candidate’s method in 3(a)(i), e.g. accept alternative method using £44 or £396 (if originally found from subtraction, sight of appropriate multiplication or division, or vice versa) If values are used, FT provided the 3 values total (£)660 If a total is given in a response it must be correct, (£)660 Allow, e.g. 'multiply Aled's mother's amount by 3', |
| Scheme | Marks | Comments |
|---|---|---|
Sight any of any one of the following:
| B1 | Allow 1.13 (kg) provided it is interpreted correctly Accept evidence in working, do not award if working is not seen If units are given they must be correct |
| Coat AND Jumper (820 + 320) | B2 | Do not award B2 unless either previous B1 awarded or appropriate correct working shown Do not award B2 if incorrect working or no working seen B1 for any of the following:
21130 – 820 – 320 = 19 990 or 820 + 320 = 1140 OR B1, B1 for sight of 21130 – 820 – 320 = 19 990 |
| Scheme | Marks | Comments |
|---|---|---|
| (i) Appropriate calculation, e.g. 9 × 11.4(0), 34.2(0) + 68.4(0), 3 × 34.2(0), 45.6(0) + 57(.00), (45.6 + 5.7) × 2 | M1 | Calculation that could lead to the correct answer if evaluated correctly |
| 102.6(0) (euros) | A1 | |
| (ii) Appropriate calculation, e.g. 11.4(0) ÷ 2 + 22.8(0), 57(.00) ÷ 2, (34.20 + 22.80) ÷ 2 | M1 | Calculation that could lead to the correct answer if evaluated correctly |
| 28.5(0) (euros) | A1 |
| Scheme | Marks | Comments |
|---|---|---|
| (i) Correctly completed frequency diagram | B1 | Bars of correct height (16 and 33) for the missing intervals |
| (ii) \(1.12 \leq b \lt 1.16\) | B1 |