Numeracy Higher November 2023 Unit 1 Q4
4. Giovanni has a takeaway pizza van. He sells whole pizzas and slices of pizza from his van.
Giovanni recorded his results in the table below.
| Time, \(t\) (minutes) | Frequency | Cumulative frequency |
|---|---|---|
| \(3 \lt t \leqslant 5\) | 8 | 8 |
| \(5 \lt t \leqslant 7\) | 24 | 32 |
| \(7 \lt t \leqslant 9\) | 74 | 106 |
| \(9 \lt t \leqslant 11\) | 40 | …………… |
| \(11 \lt t \leqslant 13\) | 14 | …………… |

Use your cumulative frequency diagram to give the best estimates for the answers to each of the following questions.
The median time is …………… minutes.
He says,
“Only 25% of the food orders are completed in under …………… minutes.”
Use one of the five values below to complete Giovanni’s statement. [1]
6·4 6·6 7·2 8 9·6
- Giovanni spent £180 on ingredients
- he spent £220 on the running costs for the pizza van
- he received a total of £700 from the food orders.
Calculate Giovanni’s percentage profit. [3]
This is an increase of 20% from the current charge.
Calculate how much Giovanni currently charges for a basic pizza. [2]
| Scheme | Marks | Comments |
|---|---|---|
| (i) Entries 146 and 160 in the table and the cumulative frequency diagram completed correctly (correct plots (11, 146) and (13, 160) and all plots joined) | B2 | B1 for any one of the following:
|
| (ii) 8.2 to 8.4 (minutes) | B1 | Answer space takes precedence Allow 8 minutes 12 seconds to 8 minutes 24 seconds FT reading from the graph for ‘their median’, from ½ × ‘their 160’, provided ‘their 160’ ≥ 110, with a tolerance of ½ small square from ‘their cumulative frequency graph’, provided it is possible to read ‘their median’ from the vertical axis on the graph paper provided |
| (iii) 7.2 minutes | B1 | Answer space in the statement takes precedence, if blank award for indication of ‘7.2’ (circled) in the list Allow ‘7’ in the answer space provided 7.2 indicated in the list Do not accept ‘8’ in the answer space if 7.2 indicated in the list |
| (iv) \(\frac{20}{160}\) ( × 100) or \(\frac{1}{2}\) × 25 (%) or equivalent | M1 | FT for (100 ×) 20/‘their 160’, provided ‘their 160’> 106 |
| 12.5 (%) or 12½ (%) | A1 | On FT allow rounding or truncation to 1 decimal place |
| Scheme | Marks | Comments |
|---|---|---|
| (Costs are 180 + 220) (£) 400 AND (Profit is 700 – 180 – 220) (£) 300 OR (Receipts / Costs =) \(\frac{700}{400}\) (× 100) | B1 | May be embedded, e.g. 700 – 400 = 300 (= 1.75 or 175%) |
| (Percentage profit is) \(\frac{300}{400}\) (× 100) or \(\frac{700}{400}\) (× 100) – 1 (× 100) | M1 | FT ‘their 400’ and 700 – ‘their 400’ provided their costs or profit are ≠ 180, ≠ 220 and ≠ 700 |
| 75 (%) | A1 | CAO Allow if all costs and the total are consistently multiplied by 3. |
| Scheme | Marks | Comments |
|---|---|---|
| 8(.)40 ÷ 1(.)20 or 8(.)40 – 8(.)40 ÷ 6 or equivalent | M1 | Accept a complete and convincing method of trial and improvement |
| (£) 7 or 700 (p) | A1 | If units are given they must be correct Sight of 7 + 1.40 = 8.40 is awarded M1 A0 unless (£)7 is selected |