Numeracy Intermediate June 2017 Unit 2 Q6
6.
Gustav is making some scones for his sister’s birthday party.
Recipe to make 12 scones
450 g self raising flour
2 teaspoons of baking powder
75 g butter
50 g caster sugar
2 eggs
225 ml milk
Bake at 428°F for 10 to 15 minutes
How much self raising flour will Gustav need to make 30 scones?
Circle your answer. [1]
900 g 1000 g 1100 g 1125 g 1350 g
In the recipe, the temperature of the oven is given in degrees Fahrenheit, F.
The temperature gauge on Gustav’s oven shows degrees Celsius, C.
The formula below is used to convert Fahrenheit into Celsius.
\[C = \frac{5F - 160}{9}\]At what temperature should Gustav bake the scones?
Give your answer in degrees Celsius. [2]
…………… °C
Gustav also makes a birthday cake for his sister.
The top face of the cake is in the shape of a trapezium.
Diagram not drawn to scale
Gustav plans to ice the top face of the cake.
Each packet of icing costs £1.35 and is enough to cover 65 cm2.
He has to buy complete packets of icing.
Calculate the area of the top face of the cake Gustav has made. [2]
From the formula list: Area of trapezium \(= \dfrac{1}{2}(a+b)h\)
How much will it cost Gustav to ice the top face of the cake?
You must show all your working. [3]
Gustav also plans to decorate the cake with small pieces of marzipan shaped as shown below.
The top face of each piece of marzipan is a rhombus.
Will these pieces of marzipan tessellate?
Yes ☐ No ☐
Draw a simple diagram to support your answer. [1]
Corrected by Westie's Workshop
- The board's question paper printed “Give you answer in degrees Celsius.”. Changed to “Give your answer in degrees Celsius.” because “you” is a misprint for “your”.
Original: see the board's question paper PDF (link above).
| Scheme | Marks | Comments |
|---|---|---|
| (i) 1125 g | B1 | |
| (ii) \(\dfrac{5 \times 428\ - 160}{9}\) | M1 | Needs to show intention to calculate 5×428 These answers imply M0, A0
|
| 220 (°C) | A1 | CAO |
| Scheme | Marks | Comments |
|---|---|---|
| (i) ½ × 12 × (15 + 20) 210 (cm2) | M1 A1 | Accept working seen in (b)(ii) |
| (ii) 210 ÷ 65 (=3.23…) OR 4 × 65 (= 260) OR 65 + 65 + 65 + 65 (= 260) OR equivalent | M1 | Accept working may be seen in (b)(i) FT ‘their 210’ provided > 130 Sight of 3 × 65 = 195 and 4 packets is selected implies M1 |
| 4 (packets) × 1.35 | m1 | Depends on the award of the previous M1 FT ‘their 210’÷ 65 provided
|
| (£)5.4(0) | A1 | FT provided rounding up was necessary for the number of packets Allow £5.4(0)p |
| (iii) Yes (indicated or implied) AND showing at least 4 of the given shape to make 360° | E1 | The 4 shapes may include the one given Accept intention of congruent shapes and straight lines (use of a ruler is not required) Allow if intention is clear, but free hand size of the congruent shapes changes, or if shapes don’t quite touch (as it is being shown how they would be placed, i.e. slight gaps as if the shapes were tiles with grouting), or showing intention of 4 shapes meeting at a point (allow some drift in adding extra tiles) Do not accept a line of shapes without the 360° The shape must clearly not be a square or rectangle. |