Foundation June 2019 Unit 2 Q12
12.
(a) Find the value of \(5f + 7g\) when \(f\) = 3·8 and \(g\) = −2·6. [2]
(b) Solve the following equation.
Give your answer correct to 1 decimal place. [3]\[7x - 4 = 12\]
Give your answer correct to 1 decimal place. [3]\[7x - 4 = 12\]
| Scheme | Marks | Comments |
|---|---|---|
| (19 − 18·2 =) 0·8 | B2 | B1 for sight of 19 OR sight of −18·2. BUT B0 for 19f − 18·2g. Mark final answer. |
| Scheme | Marks | Comments |
|---|---|---|
| 7x = 16 | B1 | |
| ( x =) 16/7 | B1 | FT from 7x = k. Allow 16 ÷ 7 |
| (x=) 2·3 (to 1dp) | B1 | FT from any fraction that requires rounding. Mark final answer. (x =) 2·2…. implies B1B1B0. Allow an embedded 2·3, B1B1B0 |