(b) Draw the graph of \(y = x^2 + x - 4\) for \(-4 \leqslant x \leqslant 3\).[3]
(c) Use your graph to solve \(x^2 + x - 4 = 0\). [2]
(d) On the same grid, draw the graph of \(y = -2x - 1\) for \(-4 \leqslant x \leqslant 3\).
You may use the table if you wish.
\(x\)
−4
\(y\)
7
[3]
(e) Use your graphs to solve the equation \(x^2 + x - 4 = -2x - 1\). [2]
Mark scheme (a)
Answer
Marks
Part marks and guidance
8 −2 −2 8
2
B1 for any 2 correct
Mark scheme (b)
Answer
Marks
Part marks and guidance
correct curve which dips below the line \(y = -4\)
3
B2 for 6 or 7 points correctly plotted FTtheir table or B1 for 4 or 5 points correctly plotted FTtheir table
tolerance ± 2 mm for plotting and the curve through the correct points
Mark scheme (c)
Answer
Marks
Part marks and guidance
−2.7 to −2.5 1.5 to 1.7
2
B1 for each Correct answer or FT their graph
tolerance ± 2 mm
Mark scheme (d)
Answer
Marks
Part marks and guidance
correct ruled line
3
M2 for a correct unruled line or a line of gradient −2 or a line going through (0, −1) or two further correct points in the table or plotted or M1 for one point correctly plotted or one further correct point in the table
points are
\(x\)
−3
−2
−1
0
1
2
3
\(y\)
5
3
1
−1
−3
−5
−7
tolerance ± 2 mm
Mark scheme (e)
Answer
Marks
Part marks and guidance
−3.9 to −3.7 [0].7 to [0].9
2
B1 for each Correct answer or FTtheir straight line