Higher June 2023 Paper 2 Q23
23 Here are three similar triangles, \(ABG\), \(ACF\) and \(ADE\).
\(ABCD\) and \(AGFE\) are straight lines.
\(AB : BC : CD = 1 : 2 : 3\)
Show that
area of \(ABG\) : area of \(BCFG\) : area of \(CDEF\) = 1 : 8 : 27 (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| Shown | M1 | for start to process using ratio, eg \(1 : 1 + 2 : 1 + 2 + 3\ (= 1 : 3 : 6)\) |
| M1 | for process to write down ratio of areas of triangles eg \(1^2 : 3^2 : 6^2\ (= 1 : 9 : 36)\) | |
| C1 | for correct working leading to answer, eg \(1 : 9 - 1 : 36 - 9 = 1 : 8 : 27\) |
Additional guidance
Values may not be seen in a ratio, can still award M marks
May be seen combined with algebra