AS June 2022 Q3
3. Gabriela is investigating a particular type of fish, called bream. She wants to create a model to predict the weight, \(w\) grams, of bream based on their length, \(x\) cm.
For a sample of 27 bream, some summary statistics are given below.
\[\bar{x} = 31.07 \qquad \bar{w} = 628.59 \qquad \sum w^2 = 11\,386\,134\]\[\mathrm{S}_{xw} = 13\,082.3 \qquad \mathrm{S}_{xx} = 260.8\]A residual plot for these data is shown below.

One of the bream in the sample has a length of 32 cm.
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{S}_{ww} = 11\,386\,134 - 27(628.59)^2\ [= 717\,748.5213]\) | B1 | 1.1b |
| \(r = \dfrac{13\,082.3}{\sqrt{260.8 \times \text{‘}717\,748.5213\text{’}}}\) | M1 | 1.1b |
| \(r = 0.95618\ldots\) awrt 0.956 | A1 | 1.1b |
| (3) |
Notes
B1: Correct expression for \(\mathrm{S}_{ww}\) (implied by a correct answer)
M1: Complete method to find \(r\) (Use of \(\mathrm{S}_{ww}\) = 11 386 134 is M0)
A1: awrt 0.956
| Scheme | Marks | AO |
|---|---|---|
| Since \(r\) is close to 1, data is consistent with a linear model. | B1 | 2.4 |
| (1) |
Notes
B1: Correct explanation and conclusion
| Scheme | Marks | AO |
|---|---|---|
| \(b = \dfrac{13\,082.3}{260.8}\ [= 50.162\ldots]\) | M1 | 3.3 |
| \(a = 628.59 - \text{‘}b\text{’}(31.07)\) | M1 | 1.1b |
| \(w = -930 + 50.2x\) | A1 | 1.1b |
| (3) |
Notes
M1: Setting up linear model by finding gradient
M1: Attempting \(y\)-intercept of linear model
A1: Correct model with \(b\) = awrt 50.2 and \(a\) = awrt –930 (must use \(w\) and \(x\))
| Scheme | Marks | AO |
|---|---|---|
| \(w = -930 + 50.2(32) + 80\) | M1 | 3.4 |
| \(w = 756.4\) | A1 | 1.1b |
| (2) |
Notes
M1: Using the model with the residual. Allow \(\pm\) 80
A1: awrt 756 (allow awrt 755 from use of exact values)
| Scheme | Marks | AO |
|---|---|---|
| Negative residuals for all 5 observations with \(x \gt 33\) suggests the model systematically overestimates weights for the longest bream. | B1 | 3.5a |
| (1) | ||
| (10 marks) |
Notes
B1: Evaluating the model for \(x \gt 33\) (must reference both the residuals and the model)
Negative correlation between residuals and length is B0.