Foundation November 2020 Paper 2 Q20
20
(a) \(a\) and \(b\) are whole numbers.
\(a \leqslant 12 \qquad b \lt 9\)
Work out the largest possible value of \(\quad 2a + b\) [2 marks]
(b) \(x\) and \(y\) are both negative numbers.
Show that \(\dfrac{y}{x}\) could equal 4 [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \((24 + 8 =)\ 32\) | B2 | B1 \((2a =)\ 2 \times 12\) or \((2a =)\ 24\) or \((b =)\ 8\) |
Additional guidance
| 32 with no incorrect working | B2 |
| 32 from incorrect working eg \(22 + 10 = 32\) | B0 |
| \(24 + 9 = 33\) | B1 |
| \(22 + 8 = 30\) | B1 |
| \(24a\) without a B1 response | B0 |
| \(8b\) without a B1 response | B0 |
| \(24a + 8b\) without a B1 response | B0 |
| Use of inequalities in answer without a B1 response | B0 |
| Answer | Mark | Comments |
|---|---|---|
| An example where \(x\) and \(y\) are both negative and \(\dfrac{y}{x} = 4\) | B1 | eg \(x = -1\) and \(y = -4\) values of \(x\) and \(y\) can be implied eg \(\dfrac{-12}{-3}\ (= 4)\) |
Additional guidance
| Correct use of \(\div\) instead of fractions is allowed eg \(-12 \div -3\) | B1 |
| Must show the fraction or division or state which is \(x\) and which is \(y\) eg \(-1\) and \(-4\) | B0 |
| Decimals and / or fractions may be used eg \(\dfrac{-6.4}{-1.6}\) or \(\dfrac{-2}{-\frac{1}{2}}\) | B1 |
| One correct example among several attempts | B1 |