14 Here is a cuboid of length 10 cm and width 4 cm.
The cuboid has a volume of 200 cm3
(a) Work out the height of the cuboid. (2)
Here is a different cuboid.
(b) Work out the total surface area of this cuboid. (3)
Mark scheme (a)
Answer
Mark
Mark scheme
5
P1
for a start of a method to find the height, eg \(10 \times 4\ (= 40)\) or \(200 \div 10\ (= 20)\) or \(200 \div 4\ (= 50)\)
or for forming a correct equation \(10 \times 4 \times h = 200\)
A1
cao
Mark scheme (b)
Answer
Mark
Mark scheme
126
M1
for a start to find the area of at least one face, eg \(6 \times 3\ (= 18)\) or \(5 \times 3\ (= 15)\) or \(6 \times 5\ (= 30)\)
M1
for combining the area of at least three of the correct faces eg \(\text{``}18\text{''} + \text{``}15\text{''} + \text{``}30\text{''}\ (= 63)\) or \(2 \times \text{``}18\text{''} + \text{``}15\text{''}\)
A1
cao
Additional guidance
Do not award first M if multiplied by a third length (ie volume calculation)
May be part of a larger addition including incorrect areas. Do not award if more than 6 areas added.
The crate is 3 m by 1 m by 1.5 m. The crate is completely filled with boxes. Each box is 20 cm by 10 cm by 75 cm.
Work out the number of boxes in the crate. (4)
Mark scheme
Answer
Mark
Mark scheme
300
B1
(indep) for process to convert to common units, eg \(3 \times 100\ (= 300)\) or \(1 \times 100\ (= 100)\) or \(1.5 \times 100\ (= 150)\) or \(20 \div 100\ (= 0.2)\) or \(10 \div 100\ (= 0.1)\) or \(75 \div 100\ (= 0.75)\) or \(\text{``}4.5\text{''} \times 100^3\ (= 4\,500\,000)\) or \(\text{``}15\,000\text{''} \div 100^3\ (= 0.015)\)
P1
for finding the volume of either shape, eg \(3 \times 1 \times 1.5\ (= 4.5)\) or \([300] \times [100] \times [150]\ (= 4\,500\,000)\) or \(20 \times 10 \times 75\ (= 15\,000)\) or \([0.2] \times [0.1] \times [0.75]\ (= 0.015)\)
OR
for start of the process to find the number of boxes using one dimension, eg \([300] \div 20\ (= 15)\) or \([100] \div 10\ (= 10)\) or \([150] \div 75\ (= 2)\) or \(3 \div [0.2]\ (= 15)\) or \(1 \div [0.1]\ (= 10)\) or \(1.5 \div [0.75]\ (= 2)\)
P1
(dep on P1) for a complete process with or without unit conversion eg \(\text{``}4\,500\,000\text{''} \div \text{``}15\,000\text{''}\) or \(\text{``}4.5\text{''} \div \text{``}0.015\text{''}\)
or \(\text{``}15\text{''} \times \text{``}10\text{''} \times \text{``}2\text{''}\)
A1
cao
Additional guidance
This mark can be awarded at any stage One correct conversion for their process is enough for the award of this mark Working may be seen on the diagram
[300] = 3 or 30 or “300” or 3000 [100] = 1 or 10 or “100” or 1000 [150] = 1.5 or 15 or “150” or 1500 [0.2] = 20 or 2 or “0.2” or 0.02 [0.1] = 10 or 1 or “0.1” or 0.01 [0.75] = 75 or 7.5 “0.75” or 0.075
May be implied by correctly dividing the areas of the corresponding faces eg \(\dfrac{[300] \times [100]}{20 \times 10}\)
Condone an incorrect attempt to convert volume before division
Correct method or evaluation of the area of any face or correct method or evaluation of the volume of any relevant cuboid of length 6 cm
M1
eg \(5 \times 6\) or 30 or \(2 \times 6\) or 12 or \(3 \times 6\) or 18 or \(4 \times 6\) or 24 or \(2 \times 5 + 2 \times 2\) or \(10 + 4\) or 14 or \(2 \times 5 \times 6\) or 60 or \(2 \times 2 \times 6\) or 24 or \(2 \times 3 \times 6\) or 36 or \(4 \times 2 \times 6\) or 48 or \(5 \times 4 \times 6\) or 120
Correct method for volume of prism
M1dep
eg \(2 \times 5 \times 6 + 2 \times 2 \times 6\) or \(60 + 24\) or \(14 \times 6\)
84
A1
Additional guidance
The first M1 may be awarded even if this is seen amongst multiple attempts