Foundation November 2024 Paper 3 Q13
13 The diagram shows a crate and a box.
The crate is 3 m by 1 m by 1.5 m.
The crate is completely filled with boxes.
Each box is 20 cm by 10 cm by 75 cm.
Work out the number of boxes in the crate. (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| 300 | B1 | (indep) for process to convert to common units, eg \(3 \times 100\ (= 300)\) or \(1 \times 100\ (= 100)\) or \(1.5 \times 100\ (= 150)\) or \(20 \div 100\ (= 0.2)\) or \(10 \div 100\ (= 0.1)\) or \(75 \div 100\ (= 0.75)\) or \(\text{``}4.5\text{''} \times 100^3\ (= 4\,500\,000)\) or \(\text{``}15\,000\text{''} \div 100^3\ (= 0.015)\) |
| P1 | for finding the volume of either shape, eg \(3 \times 1 \times 1.5\ (= 4.5)\) or \([300] \times [100] \times [150]\ (= 4\,500\,000)\) or \(20 \times 10 \times 75\ (= 15\,000)\) or \([0.2] \times [0.1] \times [0.75]\ (= 0.015)\) OR for start of the process to find the number of boxes using one dimension, eg \([300] \div 20\ (= 15)\) or \([100] \div 10\ (= 10)\) or \([150] \div 75\ (= 2)\) or \(3 \div [0.2]\ (= 15)\) or \(1 \div [0.1]\ (= 10)\) or \(1.5 \div [0.75]\ (= 2)\) | |
| P1 | (dep on P1) for a complete process with or without unit conversion eg \(\text{``}4\,500\,000\text{''} \div \text{``}15\,000\text{''}\) or \(\text{``}4.5\text{''} \div \text{``}0.015\text{''}\) or \(\text{``}15\text{''} \times \text{``}10\text{''} \times \text{``}2\text{''}\) | |
| A1 | cao |
Additional guidance
This mark can be awarded at any stage
One correct conversion for their process is enough for the award of this mark
Working may be seen on the diagram
[300] = 3 or 30 or “300” or 3000
[100] = 1 or 10 or “100” or 1000
[150] = 1.5 or 15 or “150” or 1500
[0.2] = 20 or 2 or “0.2” or 0.02
[0.1] = 10 or 1 or “0.1” or 0.01
[0.75] = 75 or 7.5 “0.75” or 0.075
May be implied by correctly dividing the areas of the corresponding faces
eg \(\dfrac{[300] \times [100]}{20 \times 10}\)
Condone an incorrect attempt to convert volume before division