Numeracy Higher November 2017 Unit 2 Q9
9. An engineering company employs 85 staff.
The company plans to carry out a survey on staff health.
It will conduct the survey using a sample of 15 of its staff, stratified by job type.
| STATEMENT | ||
|---|---|---|
| Choosing every 4th person on an alphabetical list of office staff is a suitable method of randomly choosing the office staff required for the sample. | TRUE | FALSE |
| Numbering the cleaning staff, placing the numbers in a hat and drawing out numbers at random is a suitable method of choosing the cleaners required for the sample. | TRUE | FALSE |
| There are 9 managers employed by the company. The calculation to find the number of managers in the sample is \(\dfrac{9}{85} \times 15 = 1{\cdot}59\). This answer means there will definitely be 2 managers in the sample. | TRUE | FALSE |
| The proportion of the staff in each job type in the sample will be exactly the same as the proportion of the staff in each job type in the company as a whole. | TRUE | FALSE |
Use the following extract from a table of random digits to choose 9 engineers for the sample.
You must start with the first number in the list.
Describe clearly how you are using the numbers to select the sample. [3]
29974 55479 07248 33999 17038 02475 49979 01218
The building is in the form of half a cylinder, with half a hemisphere attached at one end.

Diagrams not drawn to scale
The company needs to paint all the exterior surfaces of the building, including the doors.
The measurements on the diagram are given correct to the nearest metre.
The paint comes in tins that cover an area of 40 m2, correct to the nearest m2.
From the formula list: Surface area of sphere \(= 4\pi r^2\)
Calculate the smallest number of tins that would guarantee having enough paint to cover these exterior surfaces. [8]
| Scheme | Marks | Comments |
|---|---|---|
| False True False False | B2 | B1 for 3 correct |
| Scheme | Marks | Comments |
|---|---|---|
| E2 | All 4 needed for E2 Allow an equivalent numbering system e.g. 00 to 49. E1 for any 2 or 3 correct statements. |
| (The engineers chosen would be) 29, 45, 07, 24, 39, 17, 03, | B1 | Needs to be written in this order Alternative method:
E1 for any 2 or 3 statements B1 for 29, 47, 45, 04, |
| Scheme | Marks | Comments |
|---|---|---|
| Sight of 24·5 or 12·25 AND 43·5 | B1 | Accept use of ·49 repeated and 12·249 repeated throughout, but not ·49 and 12·249 |
| (S.area of half-hemisphere =) (4 × π × 12·252) ÷ 4 or equivalent | B1 | (= 471 to 471·6… (m2)) FT ‘their 12·25’ provided it is > 11·5 and < 12·5 |
| (Curved surface area of cylinder =) (π × 24·5 × 43·5) ÷ 2 or equivalent | B1 | (= 1673 to 1674·75 (m2)) FT ‘their 24·5’ or ‘their 12·25’ and ‘their 43·5’ including use of 24 or 12, 43 and their lower bounds. |
| (Total surface area =) (4×π×12·252)÷4 + (π×24·5×43·5)÷2 + (π×12·252)÷2 | M2 | (Area of semicircle 235·5 to 235·8…) Upper bounds need to be correct. M1 for summing 3 terms, with 2 being correct. |
| = 2379·5 to 2382 (m2) | A1 | CAO |
| (Number of tins needed =) (2379·5 to 2382) ÷ 39·5 | M1 | (= 60·2… to 60·3) FT their total area provided at least M1 awarded. |
| = 61 | A1 | FT a correctly rounded up answer to their calculation. |