Numeracy Higher June 2023 Unit 1 Q7
7.
- a base area of exactly 40 cm2,
- a height of 13 cm, correct to the nearest cm.
Calculate the least possible volume of a carton. [2]
Drink is poured into each carton at a rate of 8000 cm3 per minute, correct to the nearest 1000 cm3 per minute.

Diagram not drawn to scale
Calculate the greatest possible number of cartons that the automated system could fill in an hour.
You can ignore the time taken in moving from one full carton to the next empty one. [3]
Each of these cartons has:
- a square base,
- a height of exactly 20 cm,
- a volume of exactly 960 cm3.
Calculate the length of the side of the base of one of these cartons.
Give your answer in the form \(a\sqrt{b}\), where \(a\) and \(b\) are integers and \(b\) is as small as possible. [4]
| Scheme | Marks | Comments |
|---|---|---|
| (Least possible volume of a carton =) 40 × 12.5 = 500 (cm3) | M1 A1 | Allow use of 12 < h < 13 for M1 only CAO If no marks awarded, SC1 for use of 12.5 |
(ii)
| Scheme | Marks | Comments |
|---|---|---|
| Use of 8500 | B1 | Allow 8499.999(…) for 8500 |
| \(\dfrac{8500}{500}\) (× 60) | M1 | FT ‘their 500’ from (a)(i) If B0, FT provided unambiguously chosen: 8000 < ‘their 8500’ < 9000 |
| = 1020 | A1 | CAO for ‘their 500’ from (a)(i) |
| Scheme | Marks | Comments |
|---|---|---|
| (length2 =) 960 ÷ 20 length2 = 48 OR (length =) √48 | M1 A1 | Or equivalent e.g. \(\sqrt{4} \times \sqrt{12}\) |
| (length =) 4√3 | B2 | Mark final answer Accept 40√3 mm, but not 0.04√3 m For B2, FT ‘their derived 48’ provided of equivalent difficulty (it has a square number as one of its factors) For B1, FT 'their derived 48' B1 for writing 48 as a product of 2 or more factors where one of the factors OR the product of 2 of their factors is a square number e.g. 16 × 3 or 4 × 4 × 3 or 4 × 12 or 2 × 2 × 12 OR B1 for writing \(\sqrt{48}\) as a product of 2 or more factors where one of the factors OR the product of 2 of their factors gives a whole number e.g. \(\sqrt{16} \times \sqrt{3}\) or \(\sqrt{2} \times \sqrt{2} \times \sqrt{12}\) or \(2\sqrt{12}\) |