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Intermediate November 2020 Unit 1 Q14

WJECIntermediateCurrent spec6 marksDrawing & Using GraphsSolving QuadraticsSubstitution

14. The table below shows some of the values of \(y = x^2 - 4x - 3\) for values of \(x\) from –2 to 5.

\(x\)−2–1012345
\(y = x^2 - 4x - 3\)2−3−6−6−32
(a) Complete the table by finding the value of \(y\) for \(x = -2\) and the value of \(y\) for \(x = 2\). [2]
(b) On the graph paper below, draw the graph of \(y = x^2 - 4x - 3\) for values of \(x\) from –2 to 5. [2]
Graph paper with x from -2 to 5 and y from -10 to 10, 2 mm squares
(c) Draw the line \(y = 1\) on the graph paper.
Write down the values of \(x\) where the line \(y = 1\) cuts the curve \(y = x^2 - 4x - 3\). [2]

Values of \(x\)   are   ……………………  and  ……………………