Intermediate November 2019 Unit 1 Q3
3.
(a) Calculate the value of \(3x + 4y\) when \(x = -6\) and \(y = 5\). [2]
(b) Simplify the expression \(9g - 4f - 3g - 5f\). [2]
(c) Solve the equation \(3m - 7 = 8\). [2]
(d) Expand \(4(3x - 5)\). [1]
| Scheme | Marks | Comments |
|---|---|---|
| 2 | B2 | B1 for sight of −18 (not −18x) OR B1 for sight of (+)20 ( not 20y and not −20) Mark final answer. |
| Scheme | Marks | Comments |
|---|---|---|
| 6g – 9f | B2 | Must be an expression for B2. B1 for sight of (+)6g OR sight of – 9f. B1 for 6g + – 9f. Mark final answer. |
| Scheme | Marks | Comments |
|---|---|---|
| 3m = 15 | B1 | |
| m = 5 | B1 | FT from 3m = k. Accept m = k/3 (but, if on FT k is a multiple of 3, final answer must be given as a whole number.) B1B0 for ‘m = 15/3’ Mark final answer. Allow 2 marks for embedded answer BUT only 1 mark if contradicted by m ≠ 5. Allow change of letter. |
| Scheme | Marks | Comments |
|---|---|---|
| 12x −20 | B1 | Must be shown as an expression. C.A.O. Mark final answer. |