Intermediate November 2023 Unit 1 Q4
4.
(a) Find \(\dfrac{3}{7}\) of 9·17 km.
Give your answer in metres. [3]
Give your answer in metres. [3]
…………………………… metres
(b) Express 25 minutes as a percentage of 2 hours 5 minutes. [3]
| Scheme | Marks | Comments |
|---|---|---|
| 9·17 ÷ 7 × 3 or equivalent | M1 | Answer space takes precedence. May be seen in stages. |
| 3·93 (km) | A1 | |
| 3930 (m) | B1 | FT ‘their 3·93’ × 1000. |
Alternative method
| Scheme | Marks | Comments |
|---|---|---|
| 4.(a) Alternative method (converting to m first) | Answer space takes precedence. | |
| 9170 (m) | B1 | |
| 9170 ÷ 7 × 3 or equivalent | M1 | FT ‘their 9170’ ÷ 7× 3 provided that the digits 917 are seen (i.e place value error). |
| 3930 (m) | A1 |
Corrected by Westie's Workshop
- The board's mark scheme printed “Answer space takes precendence.”. Changed to “Answer space takes precedence.” because “precendence” is a misspelling of “precedence”.
Original: see the board's mark scheme PDF (link above).
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{25}{2 \times 60 + 5}\) (× 100%) or equivalent | M2 | Allow 0·2 or \(\dfrac{1}{125 \div 25}\) or \(\dfrac{1}{5}\) to imply M2. Award M1 for an attempt at \(\dfrac{25}{2\ hours\ 5\ minutes}\) but with incorrect denominator (e.g. 2·5, 2·05, 2 hours 5 minutes stated incorrectly with 2 × 60 + 5 not shown). |
| = 20 (%) | A1 | CAO Mark final answer. If no marks awarded, award SC1 for sight of 125 (minutes). |
Alternative method
| Scheme | Marks | Comments |
|---|---|---|
| 4(b). Alternative Method 125 minutes = (100%) | B1 | |
| 12·5 minutes = 10% | M1 | |
| 25 minutes = 20% | A1 | CAO Mark final answer. |