Foundation November 2022 Paper 1 Q20
20.
Tick (✓) the two correct statements about \(3xy(y + 2) \equiv 3xy^2 + 6xy\). [2]
| It is an equation. | |
| It is true for all values of \(x\) and \(y\). | |
| It is an identity. | |
| It is only true for certain values of \(x\) and \(y\). | |
| It is an inequality. | |
| It is true for only one value of \(x\) and one value of \(y\). |
In this part of the question all lengths are in centimetres.

Diagram not drawn to scale
The diagram shows a prism.
The cross-section of the prism is a triangle with height \(x\) and base \(3x\).
The volume of the prism is \(216\,\text{cm}^3\).
Use an algebraic method to find the height of the triangle. [5]
| Scheme | Marks | Comments |
|---|---|---|
| Second and third statements indicated and no others | B2 | Award B1 for one of the following:
|
| Scheme | Marks | Comments |
|---|---|---|
| May be done in parts | ||
| (Area of cross-section = ) \(\frac{1}{2} \times 3x \times x\) | M1 | Accept \(\frac{1}{2}\) base x height oe |
| (Volume = ) \(\frac{1}{2} \times 3x \times x \times 4\) | M1 | FT ‘their \(\frac{1}{2} \times 3x \times x\)’ \(\times\) 4, provided at least two terms in \(x\). |
| \(\frac{1}{2} \times 3x \times x \times 4 = 216\) oe | A1 | CAO |
| \(x^2 = 216 \times 2 \div 4 \div 3\) (= 36) | M1 | FT ‘their \(k\)’\(\times x^2 = 216\) |
| 6 (cm) | A1 | Mark final answer. FT Final 2 marks can be awarded if trials used on an equation of the form ‘their \(k\)’\(\times x^2 = 216\) to find a correct or correct FT answer. If \(x^2\) is a square number, \(x\) must be given as a whole number. Otherwise, it may be written as an unsimplified surd. |
| (7) |
Alternative
| Scheme | Marks | Comments |
|---|---|---|
| (Area of cross-section = ) \(216 \div 4\) (=54) | B1 | |
| (Area of cross-section = ) \(\frac{1}{2} \times 3x \times x\) | M1 | Accept \(\frac{1}{2}\) base x height oe |
| \(\frac{1}{2} \times 3x \times x = 54\) oe, | A1 | CAO |
| \(x^2 = 54 \times 2 \div 3\) (= 36) | M1 | FT ‘their \(k\)’\(\times x^2\) = ‘their 54’ |
| 6 (cm) | A1 | Mark final answer. FT Final 2 marks can be awarded if trials used on an equation of the form ‘their \(k\)’\(\times x^2\) = ‘their 54’ to find a correct or correct FT answer If \(x^2\) is a square number, \(x\) must be given as a whole number. Otherwise, it may be written as an unsimplified surd. |
Notes
If no marks award SC3 for a complete correct method using trials leading to an answer of 6
OR
SC2 for
a correct trial with height > 3, e.g. \(\frac{1}{2} \times 15 \times 5 \times 4\) (and comparison with 216) si
OR a correct trial with height > 3. e.g. \(\frac{1}{2} \times 15 \times 5\) and comparison with 54 si