Higher June 2025 Paper 1 Q6
6.
(a) Work out \(2\frac{1}{5} - 1\frac{2}{3}\).
Give your answer in its simplest form. [3]
Give your answer in its simplest form. [3]
(b) Calculate the value of the reciprocal of \(0{\cdot}4\).
Give your answer as a decimal. [2]
Give your answer as a decimal. [2]
(c) Estimate the value of \(\dfrac{3{\cdot}02^3 + \sqrt{4{\cdot}17\times8{\cdot}9}}{0{\cdot}289}\). [3]
| Scheme | Marks | Comments |
|---|---|---|
| \(\frac{11}{5} - \frac{5}{3}\) oe OR \(\frac{6}{5} - \frac{2}{3}\) oe OR \((2-1) + \frac{3}{15} - \frac{10}{15}\) | M1 | |
| \(\frac{33-25}{15}\) oe OR \(\frac{18-10}{15}\) oe OR \(1 - \frac{7}{15}\) | M1 | FT if error in one numerator |
| \(\frac{8}{15}\) | A1 | CAO Mark final answer. If no marks, award SC1 for sight of \(\frac{33}{15}\) and \(\frac{25}{15}\) or \(\frac{18}{15}\) and \(\frac{10}{15}\) |
Alternative method
| Scheme | Marks | Comments |
|---|---|---|
| \(\frac13 + \frac15\) | B1 | |
| \(\frac{5+3}{15}\) oe | M1 | |
| \(\frac{8}{15}\) | A1 | Mark final answer |
| Scheme | Marks | Comments |
|---|---|---|
| \(2{\cdot}5\) | B2 | B1 for \(2\frac12\) or \(\frac{10}{4}\) or \(\frac{5}{2}\) or \(\frac{1}{0{\cdot}4}\) or \(\frac{1}{\left(\frac{4}{10}\right)}\) oe or \(-2.5\) |
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{27+6}{0.3}\) | M2 | May be seen in stages. Award M1 for any one of the following:
|
| 110 | A1 | CAO Mark final answer Award a possible M2A0 for \(\frac{30+6}{0.3}\) if 27 seen but then changed to 30. |
| (8) |