4400 Higher June 2005 Paper 4 Q14
14 A farmer wants to make a rectangular pen for keeping sheep.
He uses a wall, \(AB\), for one side.
For the other three sides, he uses 28 m of fencing.
He wants to make the area of the pen as large as possible.

Diagram NOT accurately drawn
The width of the pen is \(x\) metres.
The length parallel to the wall is \((28 - 2x)\) metres.
(a) The area of the pen is \(y\) m².
Show that \(y = 28x - 2x^2\). (1)
Show that \(y = 28x - 2x^2\). (1)
(b) For \(y = 28x - 2x^2\),
(i) find \(\dfrac{\mathrm{d}y}{\mathrm{d}x}\),
(ii) find the value of \(x\) for which \(y\) is a maximum.
(iii) Explain how you know that this value gives a maximum. (5)
(c) Find the largest possible area of the pen. (2)
| Scheme | Marks |
|---|---|
| \(x(28 - 2x)\) seen | B1 |
| (1) |
Notes
B1: Brackets essential
| Scheme | Marks |
|---|---|
| (i) \(28 - 4x\) | B1 B1 |
| (ii) “\(28 - 4x\)” = 0 | M1 |
| \(x = 7\) | A1 |
| (iii) negative coeff. of \(x^2\) or ∩ shape or \(\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2} = -4\), which is negative | B1 |
| (5) |
Notes
B1B1: Ignore “\(y =\)”
B1: Not “the value is negative.”
ft her \(28 - 4x\)
| Scheme | Marks |
|---|---|
| \(28 \times 7 - 2 \times 7^2\) | M1 |
| 98 | A1 |
| (2) | |
| (8 marks) |
Notes
M1: ft his (ii) if working seen
A1: cao