November 2021 Paper 1 Q15
15 Work out the value of \(x\) where \(\quad 0^\circ \leqslant x \leqslant 90^\circ \quad\) for which \(\quad 3\tan^2 x = 1\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\tan x = (\pm)\dfrac{1}{\sqrt{3}}\) or \(\tan x = (\pm)\dfrac{\sqrt{3}}{3}\) | M1 | |
| 30 with no incorrect solutions within the given range | A1 | ignore correct solutions outside the given range. |