Foundation June 2018 Paper 1 Q7
7
(a) Solve.
(i) \(4x = 56\) [1]
(ii) \(\dfrac{126}{x} = 7\) [1]
(iii) \(8x - 6 = 46\) [2]
(b) Solve by factorising.\[x^2 + 11x + 30 = 0\]
[3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) 14 | 1 | ||
| (ii) 18 | 1 | ||
| (iii) 6.5 final answer | 2 | M1 for \(8x = 46 + 6\) or better or \(x = \dfrac{b}{a}\) from their \(ax = b\) \(a \ne 1\) | Accept \(6\frac{1}{2}\) or \(\dfrac{13}{2}\) must be an equation Accept a fully correct flow chart for M1 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(-6\) and \(-5\) final answer | 3 | B2 for \((x + 6)(x + 5)\) Or M1 for \((x \pm a)(x \pm b)\) where \((a + b) = 11\) or \((ab) = 30\) or pairs of factors giving two correct terms may be implied in a table And B1 for correct solutions FT their quadratic factors | |