Higher June 2018 Paper 4 Q16
16 Solve by factorisation.
\[3x^2 + 11x - 20 = 0\][3]| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \((3x - 4)(x + 5)\) and \(\frac{4}{3}\) oe and −5 | 3 | B2 for \((3x - 4)(x + 5)\) or B1 for two factors giving two correct terms and B1FT for two answers correct from their factors If 0 scored then B1 for two correct answers | For \(\frac{4}{3}\) accept \(1.\dot{3}\), 1.33[3…] and \(1\frac{1}{3}\) |