Higher June 2019 Paper 5 Q14
14 In the diagram AB is parallel to CD.
AED and BEC are straight lines.
Not to scale
Prove that triangle ABE is similar to triangle CDE. [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| Allow any unambiguous labelling for angles e.g. ABC or ABE or B, but not E | |||
| Angle BEA = angle CED and [vertically] opposite Angle DAB = angle ADC and alternate Angle ABC = angle DCB and alternate | M2 | For M2 only two of the three statements and reasons are required M1 for one pair of angles with a reason | Accept 3rd angle in triangle oe for reason with final angle Condone spelling e.g. alternating but not alternative |
| [Triangle ABE is similar to triangle CDE] [corresponding] angles are equal oe | A1 | With no errors or incorrect statements seen If 0 scored, SC1 for at least two correct pairs of angles identified with no / incorrect reasons | For oe allow e.g. AAA Condone identified on diagram for SC1 |