Numeracy Higher June 2022 Unit 2 Q1
1.
(a) Last year, Janita recorded the number of miles she travelled each week in her car.
She summarised the information in a frequency table, as shown below.
She summarised the information in a frequency table, as shown below.
| Number of miles, \(x\) | Frequency |
|---|---|
| \(20 \leqslant x \lt 60\) | 4 |
| \(60 \leqslant x \lt 80\) | 8 |
| \(80 \leqslant x \lt 100\) | 11 |
| \(100 \leqslant x \lt 150\) | 12 |
| \(150 \leqslant x \lt 200\) | 17 |
(i) In which group does the median weekly number of miles lie?
Circle your answer. [1]
Circle your answer. [1]
\(20 \leqslant x \lt 60\) \(80 \leqslant x \lt 100\) \(150 \leqslant x \lt 200\)
\(60 \leqslant x \lt 80\) \(100 \leqslant x \lt 150\)
(ii) Calculate an estimate of the mean number of miles Janita travelled each week in her car. [4]
(b) Last month:
- Janita travelled 440 miles in her car
- the cost of fuel was £1.30 per litre.
Janita’s car averages 11 miles per litre of fuel.
Next month, she needs to budget for an increased travel cost.
Janita says,
The number of miles I travel will increase by 12%.
The cost of fuel will increase by 10% next month.
Calculate how much Janita should budget for her car travel costs for next month.
You must show all your working. [5]
| Scheme | Marks | Comments |
|---|---|---|
| (i) \(100 \leqslant x \lt 150\) | B1 | |
| (ii) Midpoints 40, 70, 90, 125, 175 | B1 | Check the table |
| 40×4 + 70×8 + 90×11 + 125×12 + 175×17 (= 160 + 560 + 990 + 1500 + 2975 = 6185) | M1 | FT ‘their midpoints’ provided at least 4 lie within the appropriate group, including bounds throughout |
| ÷ 52 | m1 | |
| 118.9(4..miles) or 119 (miles) | A1 |
| Scheme | Marks | Comments |
|---|---|---|
| (Number of miles next month is) 440 × 1.12 | M1 | Or equivalent, e.g. 440 + 440 × 12 ÷ 100 (=440 + 52.80 = 492.80) |
| (Increased cost of fuel is) 1.3(0) × 1.1(0) | M1 | |
| (Number of miles next month is) 492.8 (miles) AND (Increased cost per litre of fuel is) (£) 1.43 | A1 | Penalise, A0, if prematurely approximated in further working, but FT for possible final A1 Penalise any premature approximation in the 1st A0 |
| (Cost of fuel next month is) \(\dfrac{440 \times 1.12}{11} \times 1.3(0) \times 1.1(0)\) or \(\dfrac{492.8}{11} \times 1.43\) | m1 | FT provided M1, M1 previously awarded |
| (£) 64.06(4) | A1 | ISW. Allow an answer of (£)64.1(0) or (£)65 Allow correctly evaluated answers from correct working which may include premature rounding or truncation, e.g. (£)64 to (£)64.10, (£)64.35 |
Alternative
1(b) Alternative method 1
| Scheme | Marks | Comments |
|---|---|---|
| (Cost of fuel last month) 1.3(0) × 440 ÷ 11 or 1.3(0) × 40 | M1 | |
| (£) 52 | A1 | May be implied in further working Penalise, A0, if prematurely approximated in further working, but FT for possible final A1 |
| (Cost of fuel next month) 52 × 1.1(0) × 1.12 | m2 | FT ‘their 1.3(0) × 440 ÷ 11’ m1 for one of the following:
|
| (£) 64.06(4) | A1 | ISW. Allow an answer of (£)64.1(0) or (£)65 FT only m2, no FT from m1. Allow correctly evaluated answers from correct working which may include premature rounding or truncation, e.g. (£)63.84, (£)64.02 |
Alternative
1(b) Alternative method 2
| Scheme | Marks | Comments |
|---|---|---|
| (Fuel next month) 1.12 × 440 ÷ 11 or 1.12 × 40 | M1 | |
| 44.8 (litres) | A1 | May be implied in further working Penalise, A0, if prematurely approximated in further working, but FT for possible final A1 |
| (Cost of fuel next month) 44.8 × 1.3(0) × 1.1(0) | m2 | FT ‘their 1.12 × 440 ÷ 11’ m1 for one of the following:
|
| (£) 64.06(4) | A1 | ISW. Allow an answer of (£)64.1(0) or (£)65 FT only m2, no FT from m1. Allow correctly evaluated answers from correct working which may include premature rounding or truncation, e.g. (£)63.84, (£)64.02 |
Alternative
1(b) Alternative method 3
| Scheme | Marks | Comments |
|---|---|---|
| (Cost of fuel next month) \(\dfrac{440 \times 1.12}{11} \times 1.3(0) \times 1.1(0)\) | M4 | Must be shown as one complete calculation to be followed by a final answer |
| (£) 64.06(4) | A1 | ISW. Allow an answer of (£)64.1(0) or (£)65 |