Foundation November 2018 Unit 2 Q14
14.
(a) Solve \(\dfrac{m}{2} = 4{\cdot}8\). [1]
(b) The \(n\)th term of a sequence is given by \(3n - 20\).
What is the value of the 6th term? [1]
What is the value of the 6th term? [1]
| Scheme | Marks | Comments |
|---|---|---|
| (m = ) 9·6 | B1 | Mark final answer. Allow embedded answer. B1 for 9·6/2 or 9·6/2 = 4·8 with no further work. B0 for 9·6/2 followed by ‘m ≠ 9·6’. |
| Scheme | Marks | Comments |
|---|---|---|
| −2 | B1 | B0 for −2n. Mark final answer. |