Intermediate November 2020 Unit 1 Q5
5.
(a) Solve the equation \(4x + 7 = 10\). [2]
(b) Simplify \(8d - 6e - 3d + 4e\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| 4x = 10 – 7 (=3) | B1 | |
| x = \(\dfrac{3}{4}\) or equivalent. | B1 | FT from 4x = b. Integer answer required if b is a multiple of 4 Mark final answer. Allow an embedded answer eg 4 × 0·75 + 7 = 10 for B2, but penalise −1 if contradicted by x ≠ 0·75 |
| Scheme | Marks | Comments |
|---|---|---|
| 5d – 2e | B2 | Must be an expression for B2. B1 for sight of (+)5d OR sight of – 2e. B1 for 5d + – 2e. Mark final answer. |