Foundation November 2017 Unit 1 Q18
18. ABCD is a quadrilateral.
\(A\hat{B}C\) = 93°, \(B\hat{C}D\) = 122° and \(A\hat{D}C\) = 85°.
Points P and Q lie on the quadrilateral as shown, such that AP = AQ.
Prove that triangle APQ is an equilateral triangle.
You must show all your working. [5]

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| Scheme | Marks | Comments |
|---|---|---|
| This is a ‘proof’ question so the work for the M1 mark must be seen before the A1 mark can be awarded. | ||
| (\(B\hat{A}D\) =) 360 – ( 85 + 122 + 93) | M1 | |
| = 60(°) | A1 | |
| (APQ = AQP = ) \(\dfrac{180 - 60}{2}\) | M1 | F.T. ‘their 60’ only if previous M1 awarded Allow reference to isosceles triangle |
| = 60(°) | A1 | |
| A convincing statement AND the three angles shown as, or stated to be 60(°) | E1 | Independent of previous marks. Must refer to three (all) angles being equal. Three angles of 60° must be shown or stated as part of a convincing statement. Reference to equal sides alone is E0. |