Higher June 2022 Paper 5 Q16
16 Work out \(0.\dot{6} \times 0.\dot{5}\dot{4}\) giving your answer as a fraction in its simplest form.
You must show your working. [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\frac{4}{11}\) final answer with correct working | 5 | “Correct working” requires \(\frac{6}{9}\) oe fraction seen and \(\frac{54}{99}\) oe fraction seen or B1 and B2 if alt method | |
| B4 for \(\frac{324}{891}\) oe with correct working isw cancelling or B1 for [\(0.\dot{6}\) =] \(\frac{6}{9}\) oe fraction B2 for \(\frac{54}{99}\) oe fraction or M1 for [100\(n\) =] 54.54… oe or better | e.g. \(\frac{36}{99}\) with correct working gets B4 oe any correct method for conversion | ||
| Alternative method: B4 for \(\frac{324}{891}\) oe with correct working or B1 for [\(0.\dot{6}\) =] \(\frac{6}{9}\) oe fraction B2 for [100\(n\) =] 36.36… or better or M1 for [\(\frac{2}{3} \times 0.\dot{5}\dot{4}\) =] \(0.\dot{3}\dot{6}\) | e.g. \(\frac{36}{99}\) with correct working gets B4 | ||
| If 0, 1 or 2 scored, instead award SC3 for \(\frac{4}{11}\) with no or insufficient working If 0 or 1 scored, instead award SC2 for answer \(\frac{324}{891}\) oe with no or insufficient working | |||