Higher June 2019 Paper 4 Q11
11 The area of a rectangle is 56 m\(^2\), correct to the nearest m\(^2\).
The length of the rectangle is 9.2 m, correct to the nearest 0.1 m.
Calculate the smallest possible width of the rectangle. [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [55.5 ÷ 9.25 or \(9.24\dot{9}\) =] 6 | 4 | 6 must not come from a rounded answer B1 for 55.5 B1 for 9.25 condone 9.2499 or better M1 for their 55.5 ÷ their 9.25 \((55.5 \leqslant\) their \(55.5 \leqslant 56.5\) and \(9.15 \leqslant\) their \(9.25 \leqslant 9.25)\) | |