Higher June 2017 Paper 5 Q10
10
(a) Solve the inequality.\[3x - 2 \gt 10\]
[2]
(b) Solve.\[6x + 2 = 5 - 4x\]
[3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(x \gt 4\) | 2 | M1 for a correct first step e.g. \(3x \gt 10 + 2\), \(3x - 12 \gt 0\) | For M1, condone wrong inequality symbol or equals |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\frac{3}{10}\) oe isw | 3 | M1 for correct first step e.g. \(6x + 4x + 2 = 5\) M1 for \(6x + 4x = 5 - 2\) or FT their \(ax = b\) to \(x = \frac{b}{a}\) | Embedded answer scores M2 max If not shown, M1 implied by \(\pm 10x = b\) or \(ax = \pm 3\) e.g. M1 for \(2x = 7\) leading to \(x = \frac{7}{2}\) oe |