Foundation November 2018 Paper 3 Q7
7
(a) Show the inequality \(x \gt 3\) on this number line.

[2]
(b) Simplify.
\(4a + 3c + 7a - 5c\) [2]
(c) Solve.
\(\dfrac{2x}{3} = 4\) [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| Hollow circle at 3 only | 1 | No other blobs | |
| Line/arrow “pointing” right from 3 | 1 | Marks independent | Open line or arrow only and condone mark/blob over 8 or x If line, must reach approx. 8 Condone line/arrow starting closer to 3 than 4 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(11a - 2c\) final answer | 2 | B1 for \(11a\) or \(-2c\) seen | Accept in any order \(11a + {-2c}\) scores 1 mark |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 6 | 2 | M1 for \(2x = 12\) or \(\dfrac{x}{3} = 2\) or \(\dfrac{x}{1.5} = 4\) | If T&I only correct answer scores Must be algebraic method for M1 Do not accept embedded answers |