Foundation June 2025 Paper 3 Q4
4
Give your answer in its simplest form. [2]
Give your answer in millilitres. [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [0].01 | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\dfrac{7}{20}\) | 2 | B1 for \(\dfrac{35}{100}\) | Allow equivalent proper fraction for B1 e.g. \(\dfrac{350}{1000}\) but not \(\dfrac{3.5}{10}\) |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 300 | 3 | M2 for \(0.15 \times 2000\) oe OR M1 for \(0.15 \times\) figs 2 oe or B1 for [2 litres =] 2000 [ml] If 0 or 1 scored, instead award SC2 for \(0.15 \times 200\) oe with answer 30 | See appendix for non-calculator methods |
Appendix
Non Calculator methods for percentages.
Labels only
This is when labels such as 10% = are used.
If only labels are used the final answer scores full marks if it is correct.
Condone a numerical slip if the answer is correct.
If there is an error in the values and so the final answer is incorrect this cannot score method marks
e.g. Find 65% of 80
| Method scoring M1A1 | 10% = 8 5% = 4 50% = 40 65% = 52 ✓ M1A1 | 10% = 8 5% = 5 ✖ condone this slip as answer correct 50% = 40 65% = 52 ✓ M1A1 |
| Method scoring M0A0 | 10% = 8 5% = 6 ✖ Do not condone this slip as answer incorrect 50% = 40 65% = 54 ✖ M0 |
Build up method
This is where the candidate finds the percentages to build up to the required value but shows the operations used.
e.g. Find 65% of 80
10% = \(80 \div 10 = x\)
5% = \(x \div 2 = y\)
50% = \(x \times 5 = z\)
65% = \(x + z + y\)
Because the operations have been shown and they are correct, if there is an error in one of \(x\), \(y\) or \(z\), method marks can still be earned