Foundation June 2019 Paper 2 Q10
10
(a) Simplify fully.
(i) \(3t + 5u - 2t + 3u\) [2]
(ii) \(6a \times 2a^2\) [2]
(b) Make \(x\) the subject of the formula \(y = x^2 - 1\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) \(t + 8u\) final answer | 2 | M1 for [+1]\(t\) or [+]\(8u\) in final answer If 0 scored SC1 for correct answer seen then spoilt | Accept \(1t + 8u\), \(8u + 1t\) Condone capitals for 2 or 1 marks eg \(t + 8u = 9tu\) |
| (ii) \(12a^3\) final answer | 2 | B1 for \(12a^k\) or \(ka^3\) (\(k \ne 0\)) | |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(x = \sqrt{y + 1}\) final answer | 2 | M1 \(\sqrt{y + 1}\) final answer or for \(x^2 = y + 1\) or for correct FT step to answer after incorrect first step | Ignore \(\pm\) or – for 2 marks or M1 Condone \(\sqrt{y + 1} = x\) For M1 condone \(y + 1 = x^2\) eg \(x = \sqrt{y - 1}\), after \(x^2 = y - 1\) seen. |