Foundation June 2018 Paper 2 Q3
3
(a) Work out.
(i) \(10^3\) [2]
(ii) \(9(8 - 3 \times 2)\) [2]
(b) Put brackets into this sum so that the answer is correct.
\(1 + 2 \times 3 + 5 = 17\) [1]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) 1000 | 2 | M1 for 10 \(\times\) 10 \(\times\) 10 | |
| (ii) 18 | 2 | M1 for 9(8 – 6) or 9 x 2 or SC1 for answer of 90 or -18 | M1 for eg 72 – 54 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(1 + 2 \times (3 + 5) = 17\) | 1 | Or \(1 + (2 \times (3 + 5)) = 17\) | Condone \(1 + 2\,(3 + 5) = 17\) if rewritten |