June 2022 Paper 2 Q11
11 A die in the form of a dodecahedron has its faces numbered from 1 to 12. The die is biased so that the probability that a score of 12 is achieved is different from any other score. The probability distribution of \(X\), the score on the die, is given in the table in terms of \(p\) and \(k\), where \(0 \lt p \lt 1\) and \(k\) is a positive integer.
| \(x\) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| \(\mathrm{P}(X = x)\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(p\) | \(kp\) |
Sam rolls the die 30 times, Leo rolls the die 60 times and Nina rolls the die 120 times. They each plot their scores on bar line graphs.
Nina rolls the die a further 30 times.
| Scheme | Marks | AO |
|---|---|---|
| Nina’s, because hers is the largest sample size oe | B1 | 2.2a |
| [1] |
Notes
B1: allow eg Nina’s, because with a larger sample size the probabilities get closer to the true probabilities oe
| Scheme | Marks | AO |
|---|---|---|
| \(11p + kp = 1\) | M1 | 3.1a |
| \(p = \frac{1}{11+k}\) | A1 | 1.1 |
| [2] |
| Scheme | Marks | AO |
|---|---|---|
| their \(\frac{1}{11+k} \times k\) or their \(\frac{1}{11+k} \times 120\) | M1 | 2.1 |
| \(120 \times\) their \(\frac{k}{11+k}\) | M1 | 1.2 |
| \(\frac{120k}{11+k}\) oe | A1 | 1.1 |
| [3] |
Notes
M1: multiply by \(k\) or by 120; may be embedded
M1: multiplying by both \(k\) and 120
| Scheme | Marks | AO |
|---|---|---|
| \(32 =\) their \(\frac{120k}{11+k}\) oe | M1 | 1.1 |
| \(k = 4\) | A1 | 1.1 |
| [2] |
Notes
Alternatively
| Scheme | Marks |
|---|---|
| \(11p = 1 - \frac{32}{120}\) may be implied by \(p = \frac{1}{15}\) (from \(\mathrm{P}(X \neq 12)\)) | M1 |
| \(k = 4\) | A1 |
M1: or \(\frac{kf}{120} = \frac{32}{120}\)
(from \(11f = 120 - 32 = 88\) so \(f = 8\) and so \(kp = \cdots\))
A1: \(k = 4\)
| Scheme | Marks | AO |
|---|---|---|
| \(Y \sim \mathrm{B}\left(30, \text{their } \frac{4}{11+4}\right)\) or \(Y \sim \mathrm{B}\left(30, \frac{32}{120}\right)\) used to find \(\mathrm{P}(Y = 8)\) | M1 | 3.1a |
| 0.16 – 0.163 BC | A1 | 1.1 |
| [2] |
Notes
M1: \(Y\) is the number of 12s obtained in 30 rolls;
A1: allow B2 for 0.1628 – 0.163 unsupported