Higher November 2020 Paper 2 Q6
6. \(ABCD\) is a parallelogram.

Diagram not drawn to scale
Work out the value of \(x\) and the value of \(y\). [5]
You must show all your working.
| Scheme | Marks | Comments |
|---|---|---|
| \(5x+40=6x+20\) | M1 | Allow for \(5\times20+40=6\times20+20\) which may be seen in stages |
| \(x=20\) | A1 | |
| \(5\times20+40+y+35=180\) OR \(6\times20+20+y+35=180\) OR \(5\times20+40+2(y+35)+6\times20+20=360\) | M2 | FT ‘their 20’ for possible M2 provided previous M1 awarded May be seen in stages. M1 for a correct equation \(5x+40+y+35=180\) or \(6x+20+y+35=180\) or \(5x+40+y+35+6x+20+y+35=360\) |
| \(y=5\) | A1 | CAO |
Alternative method (using simultaneous equations)
| Scheme | Marks | Comments |
|---|---|---|
| Writes two correct equations in \(x\) and \(y\) \(5x+40+y+35=180\) or \(6x+20+y+35=180\) or \(5x+40+y+35+6x+20+y+35=360\) | M2 | M1 for each correct equation May be simplified |
| Method to eliminate variable, e.g. equal coefficients and method to find second variable | m1 | Allow one error in one term but not with equal coefficients |
| Finds the value of the first variable | A1 | CAO \(x=20\) OR \(y=5\) |
| Second variable | A1 | FT ‘their first variable’ |
| (5) |