Higher November 2018 Paper 2 Q6
6.
Diagram not drawn to scale
The area of the right-angled triangle is 41·82 cm2.
Calculate the area of the obtuse-angled triangle. [5]
| Scheme | Marks | Comments |
|---|---|---|
| \(\tfrac12 \times 8.2 \times \text{height} = 41.82\) | M1 | |
| \(\text{height} = \dfrac{41.82}{\tfrac12 \times 8.2}\) | m1 | |
| = 10.2 (cm) | A1 | May be embedded in further calculation |
| Area \(= \tfrac12 \times 9.8 \times 10.2\) | m1 | Do not FT if clearly not perpendicular height used FT ‘their 10.2’ provided M1 previously awarded |
| = 49.98 (cm2) | A1 | FT for accurate evaluation of \(4.9 \times\) ‘their 10.2’ Accept 50 (cm2) from correct working |
| (5) |
Notes
Alternative method
| \(\dfrac{9.8}{8.2} \times 41.82\) | M4 |
| = 49.98 (cm2) | A1 |