Foundation November 2020 Paper 2 Q10
10. Jack sells ice-cream cones at a beach cafe.
Each ice-cream cone has two scoops of ice cream.
The scoops can be the same or different flavours.
There are three possible flavours to choose from:
- chocolate (C),
- vanilla (V),
- strawberry (S).
List all the possible flavour combinations for two scoops of ice cream. [2]
Two scoops of vanilla ice cream is the most popular.
Jack gets 125 single scoops of vanilla ice cream from one tub.
Each tub costs £43.50.
Jack needs to buy enough tubs to make 1300 of his two-scoop vanilla ice-cream cones.
What is the least amount Jack will need to pay? [5]
| Scheme | Marks | Comments |
|---|---|---|
| CC CV CS SS SV VV oe | B2 | B1 for 4 or 5 correct Ignore inclusion of VC, SC and VS oe |
| Scheme | Marks | Comments |
|---|---|---|
| 1300 × 2 | M1 | Method marks may be awarded in any order (= 2600) |
| ÷ 125 | M1 | (= 20.8) |
| × 43.5(0) | M1 | |
| (21 × 43.50 = ) (£)913.5(0) | A2 | CAO Award M3 A1 for (£)904.8(0) (from 20.8 × 43.50) Award M2 SC2 for (£)478.5(0) (from 11 × 43.50) Award M2 SC1 for (£)452.4(0) (from 10.4×43.50) |
| (7) |
Alternative
Alternative method finding t, the number of tubs using trial(s)
| Scheme | Marks | Comments |
|---|---|---|
| Use of trial(s) of 125 × \(t\) OR 125 ÷ 2 × \(t\) where \(t \gt 8\) | M1 | |
| \(t\) = 21 from correct calculations in relevant trial(s) seen 125 × 20 = 2500, 125 × 21 = 2625, OR 62.5 × 20 = 1250, OR 62.5 × 21 = 1312.5 | A2 | A1 if \(t\) = 21 but an error in the relevant calculation(s) seen If M1 A0 award SC1 for \(t\) = 11 with no errors in relevant calculation(s) seen 125 × 10 = 1250, 125 × 11 = 1375 |
| Calculating the cost 21 × 43.5(0) = | M1 | FT ‘their t’ for M1 only |
| (£)913.5(0) | A1 | CAO If M1 A0 award SC1 for (£)478.5(0) (from 11 × 43.50) Award M1 A1 M1 A1 for (£)904.8(0) (from trial(s) with an error) Award M1 SC1 M1 SC1 for (£)478.5(0) (from trial(s) with no error) Award M1 SC0 M1 SC1 for (£)478.5(0) (from trial(s) with an error) |
Corrected by Westie's Workshop
- The board's mark scheme printed “0R”. Changed to “OR” because the board typed a zero instead of the letter O in the word “OR”.
Original: see the board's mark scheme PDF (link above).