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Foundation June 2019 Paper 1 Q22

EduqasFoundationCurrent spec7 marksDrawing & Using GraphsSolving Quadratics

22. The table shows some of the values of \(y = x^2 + x - 1\) for \(-2 \leqslant x \leqslant 1\).

\(x\)−2−1−0·501
\(y = x^2 + x - 1\)−1−1·25
(a) Complete the table above. [2]
(b)

On the graph paper below, draw the graph of \(y = x^2 + x - 1\) for \(-2 \leqslant x \leqslant 1\). [2]

Graph paper: x from about −2.5 to 1.5 and y from −3 to 3
(c) State the equation of the line of symmetry of the curve \(y = x^2 + x - 1\). [1]
(d) Use your graph to solve \(x^2 + x - 1 = 0\). [2]