S1 June 2011 Q6
6. Jake and Kamil are sometimes late for school.
The events \(J\) and \(K\) are defined as follows
\(J\) = the event that Jake is late for school
\(K\) = the event that Kamil is late for school
On a randomly selected day, find the probability that
Given that Jake is late for school,
The teacher suspects that Jake being late for school and Kamil being late for school are linked in some way.
| Scheme | Marks |
|---|---|
| \(\mathrm{P}(J \cup K) = 1 - 0.7\) or \(0.1 + 0.15 + 0.05 =\) 0.3 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| P(\(K\)) = 0.05 + 0.15 or “0.3” – 0.25 + 0.15 or “0.3” = 0.25 +P(\(K\)) – 0.15 | M1 |
| May be seen on Venn diagram = 0.2 | A1 |
| (2) |
Notes
M1 for a complete method, follow through their 0.3, leading to a linear equation for P(\(K\))
NB You may see this Venn diagram.
Need not include box or 0.7
Correct answer only is 2/2
| Scheme | Marks |
|---|---|
| \(\left[\mathrm{P}(K \mid J)\right] = \dfrac{\mathrm{P}(K \cap J)}{\mathrm{P}(J)}\) | M1 |
| \(= \dfrac{0.15}{0.25}\) | A1 |
| \(= \underline{\dfrac{3}{5}}\) or 0.6 | A1 |
| (3) |
Notes
In parts (c) and (d) they must have defined \(A\) and \(B\)
M1 for a correct expression (including ratio) in symbols.
1st A1 for a correct ratio of probabilities (if this is seen the M1 is awarded by implication)
Must be in (c). Condone no LHS but wrong LHS (e.g. P(\(K\)) or P(\(J|K\))) is M0A0
2nd A1 for correct answer as printed only. Correct answer only 3/3
| Scheme | Marks |
|---|---|
| \(\mathrm{P}(J) \times \mathrm{P}(K) = 0.25 \times 0.2\ (= 0.05),\ \ \mathrm{P}(J \cap K) = 0.15\) or \(\mathrm{P}(K \mid J) = 0.6,\ \mathrm{P}(K) = 0.2\) or may see P(\(J|K\)) = 0.75 and P(\(J\)) = 0.25 | M1 |
| not equal therefore not independent | A1ft |
| (2) |
Notes
Mark (d) and (e) together
M1 for a correct comparison of known probabilities for an independence test - ft their values. E.g. \(\mathrm{P}(J) \times \mathrm{P}(K)\) with \(\mathrm{P}(J \cap K)\) or P(\(K|J\)) with P(\(K\)) [Must have expressions]
The values of these probabilities should be given unless they are in the question or stated elsewhere.
A1ft for correct calculations and correct comment for their probabilities
| Scheme | Marks |
|---|---|
| Not independent so confirms the teacher’s suspicion or they are linked (This requires a statement about independence in (d) or in (e)) | B1ft |
| (1) | |
| (9 marks) |
Notes
B1ft ft their conclusion on independence so not independent confirms teacher…independent contradicts teacher.
Methods leading to negative probabilities should score M0