M1 June 2007 Q5
5.

A small ring of mass 0.25 kg is threaded on a fixed rough horizontal rod. The ring is pulled upwards by a light string which makes an angle 40\(^\circ\) with the horizontal, as shown in Figure 3. The string and the rod are in the same vertical plane. The tension in the string is 1.2 N and the coefficient of friction between the ring and the rod is \(\mu\). Given that the ring is in limiting equilibrium, find
(a) the normal reaction between the ring and the rod, (4)
(b) the value of \(\mu\). (6)

| Scheme | Marks |
|---|---|
| \(\uparrow\ \ \pm R + 1.2\sin 40^\circ = 0.25g\) | M1 A1 |
| Solving to \(R = 1.7\ \ (\text{N})\) accept 1.68 | DM1 A1 |
| (4) |
| Scheme | Marks |
|---|---|
| \(\rightarrow\ \ F = 1.2\cos 40^\circ\ \ (\approx 0.919)\) | M1 A1 |
| Use of \(F = \mu R\) | B1 |
| \(1.2\cos 40^\circ = \mu R\) ft their \(R\) | DM1 A1ft |
| \(\mu \approx 0.55\) accept 0.548 | A1 cao |
| (6) | |
| (10 marks) |