4MA0 Higher June 2017 Paper 4 Q20
20 A car travels a distance of 63.5 km, correct to the nearest 0.5 km.
The car takes 45.8 minutes correct to 1 decimal place.
Work out the lower bound for the average speed of the car.
Show your working clearly.
Give your answer in km/h correct to 1 decimal place.
(4)
| Scheme | Marks |
|---|---|
| 45.75 or 45.85 or 63.25 or 63.75 | B1 |
| \(\dfrac{63.25}{45.85}\) (= 1.379)... or \(\dfrac{45.85}{60}\) (=0.764)... | M1 |
| \(\dfrac{63.25}{45.85} \times 60\) oe e.g. \(\dfrac{63.25}{0.764\ldots}\) | M1 |
| 82.8 | A1 |
| (4) | |
| (4 marks) |
Notes
B1: Accept \(45.84\dot{9}\) or 45.8499... or \(63.74\dot{9}\) or 63.7499...
M1: Or for \(\dfrac{LB_1}{UB_2}\) or \(\dfrac{UB_2}{60}\) where
\(63.25 \leqslant LB_1 \lt 63.5\),
\(45.8 \lt UB_2 \leqslant 45.85\)
M1: \(\dfrac{LB_1}{UB_2} \times 60\) oe, e.g. \(\dfrac{LB_1}{\text{'}0.764\ldots\text{'}}\)
A1: Or better (82.76990185)