4400 Higher June 2006 Paper 3 Q16
16 Part of the graph of \(y = x^2 - 2x - 4\) is shown on the grid.

(a) Write down the coordinates of the minimum point of the curve. (1)
(b) Use the graph to find estimates of the solutions to the equation \(x^2 - 2x - 4 = 0\)
Give your answers correct to 1 decimal place. (2)
Give your answers correct to 1 decimal place. (2)
(c) Draw a suitable straight line on the grid to find estimates of the solutions of the equation \(x^2 - 3x - 6 = 0\) (3)
(d) For \(y = x^2 - 2x - 4\)
(i) find \(\dfrac{\mathrm{d}y}{\mathrm{d}x}\),
(ii) find the gradient of the curve at the point where \(x = 6\) (4)
| Scheme | Marks |
|---|---|
| 1, −5 | B1 |
| (1) |
Notes
B1: Allow ± 0.1 for \(y\)-coordinate
| Scheme | Marks |
|---|---|
| Points of intersection of curve and \(x\)-axis indicated | M1 |
| 3.2 \(\quad\) −1.2 | A1 |
| (2) |
Notes
M1: May be implied by one correct solution
A1: for both values seen
Allow ± 0.1
Condone coordinates
Allow solutions to > 1dp unless there is clear evidence that the formula has been used
| Scheme | Marks |
|---|---|
| \(x^2 - 2x - 4 = x + 2\) or \(y = x + 2\) seen | M1 |
| line \(y = x + 2\) drawn | M1 |
| 4.4 \(\quad\) −1.4 | A1 |
| (3) |
Notes
M1: may be implied by 2nd M1
A1: Allow ± 0.1
Do not accept coordinates
| Scheme | Marks |
|---|---|
| (i) \(2x - 2\) | B2 |
| (ii) \(2 \times 6 - 2\) (or 10 seen) | M1 |
| 10 | A1 |
| (4) | |
| (10 marks) |
Notes
B2: B1 each term (−B1 each extra term)
M1: may be awarded if at least B1 above
A1: cao