4MA0 Higher January 2014 Paper 3R Q4
4
(a) Factorise \(\;t^2 + 6t\) (2)
(b) Solve \(\;7x - 5 = 5x - 4\)
Show clear algebraic working. (3)
Show clear algebraic working. (3)
(c) Expand and simplify fully \(\;4(2y + 3) + 2(y - 6)\) (2)
| Scheme | Marks |
|---|---|
| \(t(t + 6)\) | B2 |
| (2) |
Notes
B2: Also award B2 for \((t + 0)(t + 6)\)
B1 for factors which, when expanded and simplified, give two terms, one of which is correct.
| Scheme | Marks |
|---|---|
| \(7x - 5x = -4 + 5\) or \(2x - 5 = -4\) or \(7x = 5x + 1\) etc | M1 |
| \(2x = 1\) | M1 |
| \(\frac{1}{2}\) oe | A1 |
| (3) |
Notes
M1: for correct rearrangement with \(x\) terms on one side and numbers on the other or for correct collection of either \(x\) terms or numbers on one side in a correct equation
M1: Award also for \(-2x = -1\)
A1: Award 3 marks if answer is correct and at least one method mark scored
The mark scheme states that for this part the correct answer alone does not imply a correct method.
| Scheme | Marks |
|---|---|
| \(8y + 12 + 2y - 12\) | M1 |
| \(10y\) | A1 |
| (2) | |
| (7 marks) |
Notes
M1: For 3 terms with correct signs or 4 terms without signs
A1: Also accept \(10y + 0\)