4MA0 Foundation June 2013 Paper 1 Q15
15
(a) Multiply out \(6(n - 2)\) (1)
(b) Factorise \(p^2 - 5p\) (2)
(c) Solve \(\dfrac{7x - 3}{2} = x\)
Show clear algebraic working. (3)
Show clear algebraic working. (3)
| Scheme | Marks |
|---|---|
| \(6n - 12\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(p(p - 5)\) | B2 |
| (2) |
Notes
B2: Also accept \((p + 0)(p - 5)\) for B2
B1 for factors which, when expanded and simplified, give two terms, one of which is correct.
SC: B1 for \(p(p - 5p)\)
| Scheme | Marks |
|---|---|
| \(7x - 3 = 2x\) | M1 |
| \(7x - 2x = 3\) or \(5x = 3\) | M1 |
| \(\dfrac{3}{5}\) oe | A1 |
| (3) |
Notes
M1: for \(7x - 3 = 2x\) or \(7x - 3 = 2 \times x\) or \(\dfrac{7x}{2} - \dfrac{3}{2} = x\) oe
M1: for \(7x - 2x = 3\) or \(5x = 3\) or \(5x - 3 = 0\) or \(\dfrac{7x}{2} - x = \dfrac{3}{2}\) or \(\dfrac{5x}{2} = \dfrac{3}{2}\)
NB. All these examples could be written with all terms ‘on the other side’ eg. \(-5x = -3\) etc
A1: Award full marks if at least one method mark awarded and answer correct.