(a) Complete the table of values for \(y = x^2 - 2x - 1\)
\(x\)
\(-2\)
\(-1\)
0
1
2
3
4
\(y\)
7
\(-2\)
\(-1\)
(2)
(b) On the grid, draw the graph of \(y = x^2 - 2x - 1\) for values of \(x\) from \(-2\) to 4(2)
(c) Solve \(x^2 - 2x - 1 = x + 3\) (2)
Mark scheme (a)
Answer
Mark
Notes
\(2, -1, 2, 7\)
2
B2 for all correct (B1 for 2 or 3 correct)
Mark scheme (b)
Answer
Mark
Notes
Correct graph
2
M1 (dep on at least B1) for at least 6 points from their table plotted correctly A1 cao for fully correct graph
Mark scheme (c)
Working
Answer
Mark
Notes
\(x^2 - 3x - 4 = 0\) \((x - 4)(x + 1) = 0\)
\(-1, 4\)
2
M1 for line \(y = x + 3\) drawn correctly or for reduction to correct 3 term quadratic (=0) and : \((x \pm 1)(x \pm 4)\) or formula using \(a = 1\), \(b = -3\) and \(c = -4\), allow one sign error in the formula, or \(\left(x - \dfrac{3}{2}\right)^2 = 4 + \left(\dfrac{3}{2}\right)^2\) A1 cao
