1MA0 Foundation June 2013 Paper 1 Q29
29

On the grid, draw the graph of \(y = \frac{1}{2}x + 5\) for values of \(x\) from \(-2\) to 4 (3)
| Working | Answer | Mark | Notes | ||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| \(y = \frac{1}{2}x + 5\) drawn | 3 | (Table of values / calculation of values) M1 for at least 2 correct attempts to find points by substituting values of \(x\). M1 ft for plotting at least 2 of their points (any points plotted from their table must be plotted correctly) A1 for correct line between \(x = -2\) and \(x = 4\) (No table of values) M1 for at least 2 correct points with no more than 2 incorrect points M1 for at least 2 correct points (and no incorrect points) plotted OR line segment of \(y = \frac{1}{2}x + 5\) drawn A1 for correct line between \(x = -2\) and \(x = 4\) (Use of \(y = mx + c\)) M1 for line drawn with gradient of 0.5 OR line drawn with a \(y\) intercept of 5 M1 for line drawn with gradient of 0.5 AND with a \(y\) intercept of 5 A1 for correct line between \(x = -2\) and \(x = 4\) SC : B2 for the correct line from \(x = 0\) to \(x = 4\) |