D2 June 2011 Q2
2. The table below shows the cost of transporting one unit of stock from each of four supply points, 1, 2, 3 and 4, to each of three demand points, A, B and C. It also shows the stock held at each supply point and the stock required at each demand point. A minimal cost solution is required.
| A | B | C | Supply | |
|---|---|---|---|---|
| 1 | 31 | 29 | 32 | 20 |
| 2 | 22 | 33 | 27 | 22 |
| 3 | 25 | 27 | 32 | 20 |
| 4 | 23 | 26 | 38 | 38 |
| Demand | 35 | 25 | 30 |
Table 2 shows an initial solution given by the north-west corner method.
Table 3 shows some of the improvement indices for this solution.
| A | B | C | D | |
|---|---|---|---|---|
| 1 | 20 | |||
| 2 | 15 | 7 | ||
| 3 | 18 | 2 | ||
| 4 | 28 | 10 |
Table 2
| A | B | C | D | |
|---|---|---|---|---|
| 1 | −13 | −9 | ||
| 2 | −11 | |||
| 3 | ||||
| 4 | 1 | −7 |
Table 3
| Scheme | Marks |
|---|---|
| Adds a column of four zeros and 10. | B1 |
| (1) |
Notes
1B1: cao
| Scheme | Marks | ||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M1 A1 M1 A1 | ||||||||||||||||||||||||||||||||||||
| (4) |
Notes
The shadow costs and the missing improvement indices are shown in bold.
1M1: Finding all 8 shadow costs
1A1: cao
2M1: Finding missing four improvement indices – no extra zeros
2A1: cao
| Scheme | Marks | |||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M1 A1ft | |||||||||||||||||||||||||
| DM1 A1 | |||||||||||||||||||||||||
| (4) | ||||||||||||||||||||||||||
| (9 marks) |
Notes
1M1: A valid route, their most negative II chosen, only one empty square used, \(\theta\)’s balance.
1A1ft: consistent; their entering and exiting cells stated clearly
2DM1: An improved solution 7 entries only, (so must now be using one of my negative indices as the entering cell). Must ft from their valid route.
2A1: cao