C2 June 2007 Q9
9.

| Scheme | Marks |
|---|---|
| Sine wave (anywhere) with at least 2 turning points. | M1 |
| Starting on positive \(y\)-axis, going up to a max., then min. below \(x\)-axis, no further turning points in range, finishing above \(x\)-axis at \(x = 2\pi\) or \(360^\circ\). There must be some indication of scale on the \(y\)-axis… (e.g. 1, \(-1\) or 0.5) Ignore parts of graph outside 0 to \(2\pi\). | A1 |
| (2) |
Notes
n.b. Give credit if necessary for what is seen on an initial sketch (before any transformation has been performed).
| Scheme | Marks |
|---|---|
| \(\left(0, \dfrac{1}{2}\right),\ \left(\dfrac{5\pi}{6}, 0\right),\ \left(\dfrac{11\pi}{6}, 0\right)\) (Ignore any extra solutions) (Not \(150^\circ, 330^\circ\)) \(\left(\pi - \dfrac{\pi}{6}\right)\) and \(\left(2\pi - \dfrac{\pi}{6}\right)\) are insufficient, but if both are seen allow B1 B0. | B1, B1, B1 |
| (3) |
Notes
The zeros are not required, i.e. allow 0.5, etc. (and also allow coordinates the wrong way round).
These marks are also awarded if the exact intercept values are seen in part (a), but if values in (b) and (a) are contradictory, (b) takes precedence.
| Scheme | Marks |
|---|---|
| awrt 0.71 radians (0.70758…), or awrt \(40.5^\circ\) (40.5416…) \((\alpha)\) | B1 |
| \((\pi - \alpha)\) (2.43…) or \((180 - \alpha)\) if \(\alpha\) is in degrees. \(\left[\underline{\text{NOT}}\ \pi - \left(\alpha - \dfrac{\pi}{6}\right)\right]\) | M1 |
| Subtract \(\dfrac{\pi}{6}\) from \(\alpha\) (or from \((\pi - \alpha)\))… or subtract 30 if \(\alpha\) is in degrees | M1 |
| 0.18 (or \(0.06\pi\)), 1.91 (or \(0.61\pi\)) Allow awrt (The 1st A mark is dependent on just the 2nd M mark) | A1, A1 |
| (5) | |
| 10 |
Notes
B1: If the required value of \(\alpha\) is not seen, this mark can be given by implication if a final answer rounding to 0.18 or 0.19 (or a final answer rounding to 1.91 or 1.90) is achieved. (Also see premature approx. note*).
Special case: \(\sin\left(x + \dfrac{\pi}{6}\right) = 0.65 \Rightarrow \sin x + \sin\dfrac{\pi}{6} = 0.65 \Rightarrow \sin x = 0.15\)
\(x = \arcsin 0.15 = 0.15056...\) and \(x = \pi - 0.15056 = 2.99\) (B0 M1 M0 A0 A0)
(This special case mark is also available for degrees… \(180 - 8.62\ldots\))
Extra solutions outside 0 to \(2\pi\): Ignore.
Extra solutions between 0 and \(2\pi\): Loses the final A mark.
*Premature approximation in part (c):
e.g. \(\alpha = 41^\circ,\ 180 - 41 = 139,\ 41 - 30 = 11\) and \(139 - 30 = 109\)
Changing to radians: 0.19 and 1.90
This would score B1 (required value of \(\alpha\) not seen, but there is a final answer 0.19 (or 1.90)), M1 M1 A0 A0.